Question

What is the percent composition of MgO2H2

Answer 1

41.38 % Mg

55.17 % O

3.45 % H

Explanation:

What is the percent composition of magnesium hydroxide Mg(OH)₂?

To find the percent composition we follow the next algorithm.

First we calculate the molar mass of Mg(OH)₂:

molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2

molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole

Now we devise the next reasoning:

if in         58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H

then in   100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H

X = (100 × 24) / 58 = 41.38 % Mg

X = (100 × 32) / 58 = 55.17 % O

X = (100 × 2) / 58 = 3.45 % H

Learn more about:

percent composition

brainly.com/question/419592

#learnwithBrainly