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4 years ago

What might happen to global atmospheric carbon levels if the polar ice caps were to melt?

1 answer:

6 0

If the Arctic became completely ice-free and phytoplankton productivity levels were maintained, Arrigo and his colleagues calculated that the new carbon sink could in theory absorb an extra 160 million tonnes of carbon each year.

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During the light-independent reaction, carbon dioxide is fixed by adding it to a A. 2-carbon compound B. 3-carbon compound C. 4-

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During the light independent reaction, carbon dioxide is fixed by adding it to a 5-carbon compound

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3 years ago

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The chemical properties of an atom are primarily determined by the number of

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3 years ago

¿Cuántos moles hay en 101,64 g de (NH4)²SO⁴?

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3 years ago

If 0.500 mol of NaN3 react what mass I'm grams of nitrogen would result

klemol [59]

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3 years ago

A volume of 40.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2

Anni [7]

Answer: The concentration of KOH solution is 1.215 M

Explanation:

For the given chemical equation:

$2KOH(aq.)+H_2SO_4(aq.)\rightarrow K_2SO_4(aq.)+2H_2O(l)$

To calculate the concentration of base, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is KOH.

We are given:

$n_1=2\\M_1=1.50M\\V_1=16.2mL\\n_2=1\\M_2=?M\\V_2=40.0mL$

Putting values in above equation, we get:

$2\times 1.50\times 16.2=1\times M_2\times 40.0\\\\M_2=\frac{2\times 1.50\times 16.2}{1\times 40.00}=1.215M$

Hence, the concentration of KOH solution is 1.215 M

3 0

3 years ago