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Greeley [361]
3 years ago
8

If student D can solve 60% of multiple choice questions and Student B can solve 51% of the multiple choice questions and Student

C can solve 57%. The students are unaware of each other.
a) At least one can be solved
b) Probability at most one of them can be solved
c) Probability that neither of them can be solved
d) Exactly two them can be solved
Mathematics
1 answer:
SOVA2 [1]3 years ago
3 0
Do you know answer or not please give me answer
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\bf 2)\\\\ 3+-5\implies 3+(-5)\implies 3+(-3-2)\implies ~~\begin{matrix} 3-3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-2\implies -2 \\\\\\ 9)\\\\ -5+(-6)\implies -5+(+5-11)\implies ~~\begin{matrix} -5+5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-11\implies -11 \\\\\\ 11)\\\\ 2+(-7)\implies 2+(-2-5)\implies ~~\begin{matrix} 2-2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-5\implies -5

6 0
4 years ago
For the rational expression 2x^2-7x-15/x^2-25, do both of the following,
Mrrafil [7]

Answer:

a. \frac{2x + 3}{x+5}

b. x ≠ -5 (Vertical asymptote) and x ≠ 5 (Hole)

Step-by-step explanation:

Factor the numerator (Grouping):

2x^2 - 7x - 15              

Two numbers that multiply to -30 and add to -7 = -3 and 10

[2x^2 - 10x] + [3x - 15]

(2x + 3)(x - 5)

Factor the denominator (Difference of Two Squares):

x^2 - 25 = (x +5)(x-5)

Factored Expression:

(x - 5) can be factored out of top and bottom as a hole-

\frac{(2x + 3)(x - 5)}{(x + 5)(x - 5)} = \frac{2x + 3}{x+5}

Variable Restrictions:

Denominator ≠ 0

x + 5 = 0\\x = -5

Vertical asymptote at x = -5 ⇒ x ≠ -5

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