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3 years ago

The challenge one on the other one couldn’t see so I made another photo lol plz help

Mathematics

1 answer:

Natalka [10]3 years ago

8 0

Drawing an odd number from a bag, when the bag is full of even numbers

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6 ( f + 4 ) + 2 ( f + 4 )

Helga [31]

6(f+4) + 2(f+4)

Use the distributive property:

6f+24 + 2f + 8

Now combine like terms:

8f +32

The answer is 8f + 32

4 0

3 years ago

Read 2 more answers

What is the answer to −3 − (−1)?

vladimir1956 [14]

Answer:

-2

Step-by-step explanation:

Subtracting a negative number is adding the positive number of that

-3 + 1 += -2

4 0

3 years ago

Is the relationship between 7s in 7,742 ant the 7s in 7,785 different in anyway? Explain

melisa1 [442]

The relationship between the 7's is not different in any way because the sevens are all in the same place. The sevens are in the hundreds and thousands place.

4 0

3 years ago

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0

3 years ago

NEED HELP If you change 1 and half to Half Then how would you change half Into the same and amount

Karo-lina-s [1.5K]

Answer:

You can't substitute baking soda with conditioner so don't add more conditioner becaue you'll not get fake snow. You should go and buy more baking soda.

Good Luck

Step-by-step explanation:

4 0

3 years ago