Answer:
¬(W∨S)→¬(J∨E)
D→(B∨C)
X is true
No
Step-by-step explanation:
The hypotheses "neither water nor soft drinks can quench your thirst" translates to ¬(W∨S) ("neither nor" negates the disjunction W∨S). The "if,... then" translates to the implication symbol (arrow). The conclusion "juice will not do it, unless the juice contains electrolytes" translates to ¬(J∨E). This is because if J or E were true, then J would be true (because E implies J), contrary to the conclusion that J is false ("juice will not do it"), then J∨S is false.
The hypothesis here is "the dyer breaks" hence D is the hypothesis. The conclusion is "we will hang the clothes to dry, or take the clothes to a coin-operated laundry" which is the same as (B∨C).
The proposition p→p is always true (according to truth tables). In this case, p:=X is true, then p is true and X is true.
X∨Y is false if and only if X is false and Y is false, so both statements X,Y must be false.
Hello!
In a really simple way, 3 times our answer is 19. We can just divide to find it.
19/3= 6 1/3
Anyway, it might be nice to solve the equation for b. If a=6, then b has to be 1/3, but let's check.
18+3b=19
3b=1
b=1/3
Therefore, a+b= 6 1/3
I hope this helps!
Answer:
See answers and explanations below (along with a visual graph)
Step-by-step explanation:
For the function 
:
Amplitude: 
Period: 
Phase shift: 
Vertical shift: 
Therefore, for 
:
Amplitude: 
, which is 2 units above and below the midline (see d)
Period: 
, so the cycle will repeat every 3π units
Phase shift: 
, or π units to the left
Vertical shift: 
, or 1 unit down
The correct answer is: [B]: "40 yd² " .
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First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
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→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
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Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
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Now, we add the areas of BOTH the triangle AND the square:
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→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
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The correct answer is 50%.
Approximately the middle 50% of data is contained inside the box of a box plot.
