Excuse me,what do you mean by quadrant
Answer:
A and E
Step-by-step explanation:
substitute and odd number into every equation :)
Answer:
Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner 
is:
where :
(a and b are the length and the breath of the rectangle respectively )
![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)
Thus; the moment of inertia of the lamina about one corner is
Answer:
364.5
Step-by-step explanation:
you would need a calculator for it, unless you can do exponential math at such a degree... if you're using a PC there's a good graphing calculator at Desmos.com, it can show you how a graph looks, which shows that when n is 7, the answer is 364.5. also it wouldn't be 1093.5 because the exponent is n-1 which means that while n could be 7, you need to take away 1 before using it as an exponent.
