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erica [24]
3 years ago
5

In 1999 bus fare in atlanta was 4.70.In 1979 the fare was 2/5 of the fare in 1999 what was the fare in 1979

Mathematics
2 answers:
nadezda [96]3 years ago
6 0

Answer:

1.96 I think

Step-by-step explanation:

Gennadij [26K]3 years ago
3 0

Answer : 1.96 was the fare in 1979.

Explanation :

Bus fare in Atlanta in 1999 =4.70

\text{As we have given that in 1979 the fare was } \frac{2}{5} \text{ of the fare in 1999.}

\text{Bus fare in Atlanta in 1979=} \frac{2}{5}\times 4.70

Bus fare in Atlanta in 1979 is given by

\frac{2\times 4.70}{5}\\\\=\frac{9.80}{5}\\\\=1.96

∴ 1.96 was the fare in 1979.




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Given parallelogram MNOP, MA = x + 5, AO = y + 2, PA = 3x and AN = 2y
erma4kov [3.2K]

Answer:

The values of x and y are x = 6 and y = 9

Step-by-step explanation:

MNOP is a parallelogram its diagonal MO and PN intersected at point A

In any parallelogram diagonals:

  • Bisect each other
  • Meet each other at their mid-point

In parallelogram MNOP

∵ MO and NP are its diagonal

∵ MO intersect NP at point A

- Point A is the mid-point pf them

∴ MO and NP bisect each other

∴ MA = AO

∴ PA = AN

∵ MA = x + 5

∵ AO = y + 2

- Equate them

∴ x + 5 = y + 2 ⇒ (1)

∵ PA = 3x

∵ AN = 2y

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∴ 2y = 3x

- Divide both sides by 2

∴ y = 1.5x ⇒ (2)

Now we have a system of equations to solve it

Substitute y in equation (1) by equation (2)

∴ x + 5 = 1.5x + 2

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∴ - 0.5x + 5 = 2

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∴ - 0.5x = -3

- Divide both sides by - 0.5

∴ x = 6

- Substitute the value of x in equation (2) to find y

∵ y = 1.5(6)

∴ y = 9

The values of x and y are x = 6 and y = 9

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