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serg [7]
2 years ago
5

kelly has 47 model cars. Jamal has 58 model cars. Yesterday , jamal traded 8 model cars to kelly for 14 of her cars. How many ca

rs did kelly have before the trade
Mathematics
1 answer:
lana [24]2 years ago
4 0

Answer:

33 cars please give Brainliest

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Somebody help me !!!! HELPP please!!!
stellarik [79]
Step 1: Read and understand the problem statement.

You are given (time, depth) pairs of (20 s, 8 cm) and (40 s, 0 cm) and asked to write an equation that describes the relationship of depth (y) to time (x).

The rate of change is (0 cm -8 cm)/(40 s -20 s) = -8 cm/(20 s) = -2/5 cm/s. Then in point-slope form using the second point, the linear function rule is
  y = (-2/5)(x -40) +0
You can expand this to
  y = (-2/5)x +16
  y = -0.4x +16 . . . . . . using a decimal number for the slope

_____
If the bathtubs in your "draining race" start with the same level, the one with the steepest slope (-0.5 cm/s) will win.

8 0
3 years ago
I need help on thi and the first person who answer correctly gets a BRANLIST​ and show work​
const2013 [10]

Answer:

w<6 THE SMALL LINE UNDER THE LESS THAN SIGN IS STILL THERE I JUST CANNOT ADD IT

Step-by-step explanation:

first solve the equation to the right.

-3(2w+1) = -6w-3

now solve the whole equation

-33-w< -6w-3

-w+6w < -3+33

5w < 30

divide the 5 from both sides to simplify

5/5w < 30/5

w < 6

THE ANSWER IS w < 6

3 0
3 years ago
What is the precent of 15 is 12
kati45 [8]
100%/x%=12/15
<span>(100/x)*x=(12/15)*x       - </span>we multiply both sides of the equation by x
<span>100=0.8*x       - </span>we divide both sides of the equation by (0.8) to get x
<span>100/0.8=x </span>
<span>125=x </span>
<span>x=125

so 125%</span>
8 0
3 years ago
Read 2 more answers
The maximum height of a vehicle that can safely pass under a bridge is 12 feet 5 inches. A truck measures 162 inches in height.
Leni [432]
1 foot = 12 inches. If you multiply 12 by 12 and then add 5, you get 149. 149 is less than 162 so it will be able to fit!
8 0
3 years ago
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
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