For all the answers I will assume that all buttons both green and blue must be used.
For the first question we will start by searching all the divisors of 16;
16: 1, 2, 4, 8, 16
We will think about the numbers of green buttons that can be used as the divisors of 16. We will check if t<span>he dividend of 16 to its divisors is a divisor for 56.
</span>
1 => 16 vests with 1 green button 56/16 = 3.5
2=> 8 vests with 2 green buttons 56/8 = 7
4=> 4 vests with 4 green buttons 56/4 = 14
8=> 2 vests with 8 green buttons 56/2 = 28
16=> 1 vest with 16 green buttons 56/1 = 56
From all the above results we concluded that Lee can make:
8 vests with 2 green buttons and 7 blue buttons
4 vests with 4 green buttons and 14 blue buttons
2 vests with 8 green buttons and 28 blue buttons
1 vest with 16 green buttons and 56 blue buttons
For the second question, the <span>greatest number of vests represents the greatest common divider of 16 and 56.
</span>First, we break into prime factors
16 = 2^4
56 = 2^3 *7
The greatest common divider is 8.
<span>Lee can make 8 vests and each one will have 2 green buttons and 7 blue buttons (16/8=2 and 56/8=7)</span>
This means 35% used buses. 3+4=7, so 20% took school buses while 15% took public buses. 65%-35%=30% who mean the difference, so 30% is 360. You ask what is 15% -- that's half of that difference, or 180.
Answer:
Step-by-step explanation:
suppose the first one is x. so the other one should be 6x-94 (as said).
so : x+6x-94 = 956 . then 7x -94 = 956 . then 7x = 1050 . so x = 1050/7 . then
x = 150
We base ourselves in the one piece of crucial evidence: She has 2 quarters.
-from the rest of the problem, we know that she has 2 more NICKEL'S than QUARTERS,
(2 Quarters + 2 = 4 nickels)
she has 3 fewer nickels than dimes,
DIME - 3 = Nickels
D - 3 = 4
D = 7
7 dimes
(70 cents)
4 nickels
(20 cents)
2 quarters
(25 cents)
115 cents
or $1.15
