Answer:
64cm2
Step-by-step explanation:
(32÷4)=8
8×8=64cm2
3 + 5(c + 3) = -17
First, subtract 3 from both sides. / Your problem should look like:
Second, simplify -17 - 3 to get -20. / Your problem should look like:
Third, divide both sides by 5. / Your problem should look like:
Fourth, simplify
to 4. / Your problem should look like:
Fifth, subtract 3 from both sides. / Your problem should look like:
Sixth, simplify -4 - 3 to get -7. / Your problem should look like:
Answer:
c = -7
Answer:
D. 270 cm2
Step-by-step explanation:
2*(15*5 + 15*3 + 5*3) = 270 cm2
Answer:
1. 15x^7y^2 + 4x^3 => x^3(15x^4y^2 + 4)
2. 15x^7y^2 + 3x => 3x(5x^6y^2 + 1)
3. 15x^7y^2 + 6xy => 3xy(5x^6y + 2)
4. 15x^7 + 10y^2 => 5(3x^7 + 2y^2)
Step-by-step explanation:
To obtain the answer to the question, first let us factorise each expression. This is illustrated below:
1. 15x^7y^2 + 4x^3
Common factor is x^3, therefore the expression is written as:
x^3(15x^4y^2 + 4)
2. 15x^7y^2 + 3x
Common factor is 3x, therefore the expression is written as:
3x(5x^6y^2 + 1)
3. 15x^7y^2 + 6xy
Common factor is 3xy, therefore the expression is written as:
3xy(5x^6y + 2)
4. 15x^7 + 10y^2
Common factor is 5, therefore the expression can be written as:
5(3x^7 + 2y^2)
Answer:
1) Slope-intercept form
2) 9200
3) 2 months
4) (0,200)
Step-by-step explanation:
A shelter had 200 animals in foster homes at the beginning of spring and the number of animals in foster homes at the end of the summer could be represented by
y=3000x+200 ............ (1)
Where x is the number of months and y is the number of animals.
1) The equation (1) is written in the slope-intercept form of a straight line equation.
2) After 3 months means x = 3 and the number of animals in the foster home after 3 months will be (3000 ×3 + 200) = 9200 (Answer)
3) Let after x months the animal population will become 6200.
So, 6200 = 3000x + 200
⇒ 3000x = 6000
⇒ x = 2 months (Answer)
4) If we put x = 0 in equation (1), then we get y = 200.
So, (0,200) is a point on the graph of the line. (Answer)
