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Allisa [31]
3 years ago
12

What should you multiply if you change centimetres to millimetres

Mathematics
1 answer:
vova2212 [387]3 years ago
6 0

Answer:

  10 mm/cm

Step-by-step explanation:

The conversion factor always has a value of 1. It is a fraction with the numerator equal to the denominator -- only the units are different.

The numerator units are the units you're converting <u>to</u>: millimeters. The denominator units are the units you're converting <u>from</u>: centimeters.

You know that 1 cm = 10 mm, so when you arrange the fraction as described, the conversion factor you're multiplying by is ...

  \boxed{\dfrac{10\,\text{mm}}{1\,\text{cm}}}

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leva [86]

Considerando las fórmulas para el perímetro y el área de un rectángulo, hay que se chega en una <u>eccuación cuadrática sin solución</u>, o sea, las medidas no son posibles y la persona estaba mintiendo.

<h3>¿Cuál es la fórmula para el perímetro y el área de un rectángulo?</h3>

Considerando que las dimensiones son l y w, hay que:

  • El perímetro es: P = 2(l + w).
  • El área es: A = lw.

El <u>perímetro es de 18 m</u>, o sea:

2(l + w) = 18

l + w = 9

l = 9- w.

El <u>área es de 21 m²</u>, o sea:

lw = 21

(9- w)w = 21

-w² + 9 - 21 = 0

w² - 9w + 21 = 0

El discriminante es dado por:

D = 9² - 4 x 1 x 21 = -3.

El discriminante negativo implica que la <u>eccuación cuadrática no tiene solución</u>, o sea, las medidas no son posibles y la persona estaba mintiendo.

Puede-se aprender más a cerca de el perímetro y el área de un rectángulo en brainly.com/question/26475963

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2 years ago
Please help ASAP I NEED THIS TOMORROW!!!
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3 years ago
Two coplanar lines that are perpendicular to the same line are parallel.
Semenov [28]

Coplanar lines are <u>lines</u> that lie on the same <u>plane</u>.

Theorem: If two <u>coplanar lines</u> are <u>perpendicular</u> to the same  line, then the two lines are <u>parallel</u> to each other.

This theorem is true always, therefore, given statement is true always.

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3 years ago
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Answer:

one solution

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2/3(3y+6)=0

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3/2 *2/3(3y+6)=0*3/2

3y+6 = 0

Subtract 6 from each side

3y = -6

Divide by 3

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There is one solution

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