The ship sails at 20 km / h.
So
20 km / h x 2 h = 40 km
The boat moves 40 km to the northeast.
Then, in the same way:
20 km / h x 1 h = 20 km.
The ship moves 20 km northwest.
We solve this problem using vectors. In this case, we must perform the sum of two vectors a and b
a) magnitude = 40 km and direction 20 degrees east
b) magnitude = 20 km and direction 10 degrees northwest
In Cartesian coordinates, these vectors are written as:
a) 40sin (20º) i + 40cos (20º) j = 13,68i + 37,59j
b) -20sin (10th) i + 20cos (10th) j = -3,473i + 19,70j
The displacement vector of the ship would be the sum of a + b
a + b = 10,207i + 57,29j Finally, the magnitude of the a + b vector will tell us how far the ship is
√(10.21² + 57.29²) = 58.92km
Answer:
Let
x = number 8043
y = number 9
z = the product of 8043 and 9
z = x*y
We substitute
z = (8043)*(9)
z = 72387
Answer:
2x + 4y = 32
4x + 3y = 44
Step-by-step explanation:
From the information supplied in the question, we can see that 2 adult tickets and 4 child tickets cost $32. This means we multiply the cost of an adult ticket by 2 and add it to the product of 4 child tickets and its price I.e y.
We can also see that to get a total cost of $44, 4 adult tickets and 3 child tickets were bought. Hence, we simply multiply the cost of an adult ticket by 4 and add it to the product of 3 child ticket and its price
