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3 years ago

Which equation can be used to prove 1 + tan2(x) = sec2(x)?

Mathematics

1 answer:

notsponge [240]3 years ago

6 0

Answer:

fourth option

Step-by-step explanation:

Using the trigonometric identity

cos²x + sin²x = 1

Divide all terms by cos²x

$\frac{cos^2x}{cos^2x}$ + $\frac{sin^2x}{cos^2x}$ = $\frac{1}{cos^2x}$ which gives

1 + tan²x = sec²x

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How do you find the Median Absolute and Deviation

Ivenika [448]

Answer:

Calculate Mean Absolute Deviation (M.A.D)

Step-by-step explanation:

To find the mean absolute deviation of the data, start by finding the mean of the data set.Find the sum of the data values, and divide the sum by the number of data values.Find the absolute value of the difference between each data value and the mean: |data value – mean|.

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3 years ago

Which equation is the inverse of y = 2x2 - 8?

kirill [66]

Answer:

$y = \sqrt{ \frac{x + 8}{2} }$

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3 years ago

Show a way to count 170 to 410 using tens and hundreds circle at least 1 benchmark number

Lostsunrise [7]

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3 years ago

The following table lists the masses, in grams, of the nine planets (including dwarf planet Pluto). Use the data to choose the c

Marrrta [24]

The ratio between the masses of Jupiter and Venus is

$\dfrac{1.989\cdot 10^{30}}{4.869\cdot 10^{27}}$

We can separate the coefficient and the powers of ten:

$\dfrac{1.989\cdot 10^{30}}{4.869\cdot 10^{27}}=\dfrac{1.989}{4.869}\cdot \dfrac{10^{30}}{10^{27}}$

Use the exponent rule

$\dfrac{a^b}{a^c}=a^{b-c}$

to simplify the powers of 10:

$\dfrac{10^{30}}{10^{27}}=10^3$

So, the ratio is

$\dfrac{1.989}{4.869}\cdot 10^3\approx 0.4\cdot 10^3=400$

So, Jupiter has a mass that is approximately 400 times greater than Venus's.

4 0

3 years ago

Read 2 more answers

Which pair of numbers have a GCF of 2? Choose all answers that are correct. A. 10 and 2 B. 4 and 6 C. 6 and 12 D. 2 and 24

il63 [147K]

A.
GCF(10; 2) = 2 /factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/

B.
GCF(4; 6) = 2 /factors of 4: 1, 2, 4; factors of 6: 1, 2, 3, 6/

C.
GCF(6; 12) = 6 /factors of 6: 1, 2, 3, 6; factors of 12: 1, 2, 3, 4, 6, 12/

D.
GCF(2; 24) = 2 /factors of 2: 1, 2; factors of 24: 1, 2, 3, 4, 6, 8, 12, 24/

Answer: A, B and D.

8 0

3 years ago

Read 2 more answers