Answer:
EG = 16 and FH =22
Step-by-step explanation:
We know that the diagonals of a parallelogram bisect each other
so 2a = 3b+2
and 2a+3 = 6b-1
We know have a system of equations to solve
2a = 3b+2
2a+3 = 6b-1
Subtract 3 from each side
2a+3-3 = 6b-1-3
2a = 6b -4
Now we can set the 2 equations equal ( 2a = 3b+2 and 2a = 6b -4)
3b+2 = 6b-4
Subtract 3b from each side
3b-3b+2 = 6b-3b-4
2 = 3b-4
Add 4 to each side
2+4 = 3b-4+4
6 = 3b
Divide by 3
6/3 = 3b/3
2 =b
We want to find a
2a = 3b+2
Substitute in b=2
2a = 3(2) + 2
2a = 6+2
2a =8
Divide by 2
2a/2 =8/2
a = 4
Now that we know a and b
EG = 2a + 3b+2
= 2(4) + 3(2)+2
= 8+6+2
= 16
FH = 2a+3 + 6b-1
= 2(4) +3 +6(2)-1
= 8+3+12-1
= 23-1
= 22
Answer:the function representing profit, P = 3n + 200
Step-by-step explanation:
The function C = 2n + 200 represents his costs, in dollars, for producing n jars of salsa.
The revenue, or the amount he receives for selling n jars, can be represented by the function R = 5n.
Profit = revenue - cost or expenses.
Therefore,
The function representing Dominic's profit, P, for selling n jars of salsa will be
P = 5n - 2n + 200 = 3n + 200
To find the perimeter of any shape, you find the sum of their side lengths.
In this case, this triangle has side lengths of 1.197, 0.764, and 1.74.
Add these, and the sum is your answer.
1.197 + 0.764 + 1.74 = 3.701
Therefore 3.701 is the correct answer :)
Answer:
8
Step-by-step explanation:
Because 16 is the diameter and to find the radius you need to divide by 2
A relation is (also) a function if every input x is mapped to a unique output y.
In terms of graphical representation, this implies that a graph represents a function if there doesn't exist a vertical line that intersects the graph more than once. So:
- The first graph is exactly a vertical line, so it's not a function.
- The second graph represents the function y=x, so it's a function: you can see that every possible vertical line crosses the graph only once.
- The third graph is not a function, because you can draw vertical lines that cross the graph twice.
- Similarly, in the fourth graph you can draw vertical lines that cross the graph twice
- The fifth graph is a function, because every vertical line crosses the graph once
- The last graph is a function, although discontinuous, for the same reason.
