The cardinality of a sample space means the size of the sample space.
Event A: There are only 2 possible outcomes. Cardinality is 2.
Event B: There are 5 possible outcomes. Cardinality is 6.
The solution is the x-value of the point of intersection.
x ≈ 1 ,1 3
Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
150
Step-by-step explanation:
360 - (130 + 80) = 150
Step-by-step explanation:
-2/3f =9.2
cross multiply
27,6= -2f
divide both sides by 2
f = - 13.8
-1/8n = -2/7
cross multiply
-16 = -7n
divide
n = 2.29
12/20n = -36/44
cross multiply
528 = - 720n
divide
n= -0.733
-64.5g = -25.8
divide both sides by -64.5
g = -0.4
the last one has no variable
