Graph the system of ineqalities y<2x+2y>-x-1
1 answer:
To graph the system of inequalities you have to start with drawing both lines:
1) y=2x+2: this one is crossing points: (0,2) and (-1,0)
2) y=-x-1: this one is crossing: (0,-1) and (-1,0)
When you have it done you have to identify the area (set of points) that satisfies both inequalities. In the first case: y<2x+2, these gonna be all points below this line excluding the line (because the sign is "<"). In the second case: y<u /><u>></u>-x-1, the area includes all the points above this line including the line (because the sign is "<u>></u>").
The result is a common set of the areas: x>-1 and -x-1<y<2x+2.
Please find the graph attached!
Hope it helps!
1) y=2x+2: this one is crossing points: (0,2) and (-1,0)
2) y=-x-1: this one is crossing: (0,-1) and (-1,0)
When you have it done you have to identify the area (set of points) that satisfies both inequalities. In the first case: y<2x+2, these gonna be all points below this line excluding the line (because the sign is "<"). In the second case: y<u /><u>></u>-x-1, the area includes all the points above this line including the line (because the sign is "<u>></u>").
The result is a common set of the areas: x>-1 and -x-1<y<2x+2.
Please find the graph attached!
Hope it helps!
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