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Fed [463]
3 years ago
11

The hypotenuse of a right triangle measures 20 cm and one of its

Mathematics
2 answers:
Ket [755]3 years ago
5 0

I’m pretty sure 17.3 because of you do a^2+b^2=c^2 you get a^2= 10 square root 3 and that in a decimal is 17.3205

hammer [34]3 years ago
4 0

Answer:

8

Step-by-step explanation:

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A mummy ordered 17 bones and 8 skulls for a total of 1964. bones or $1260
kodGreya [7K]
You subtract 1260 from 1964. Then you take that number and divide it by 8.

This gives you the answer of $88 per skull.
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3 years ago
Create an equivalent system of equations using the sum of the system and the first equation.
True [87]

Answer:

D

Step-by-step explanation:

x+4y=8

4x+y=2

add

5x+5y=10

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x+4y=8

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6 0
3 years ago
Can someone help me pla
uranmaximum [27]
I believe the answer is B!

Hope this helped!
7 0
3 years ago
Read 2 more answers
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
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3 years ago
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LuckyWell [14K]

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