Ask question

Ask question

All categories

3 years ago

6

How do you graph Y equals X to the second power negative to?

1 answer:

HACTEHA [7]3 years ago

5 0

Y=1/x²

When x=-3, y=1/9

When x=-2, y=1/4

When x=-1, y=1

When x=-1/2, y=1/(-1/2)²=4

When x=0, y=undefined.

When x=1/2, y=4

When x=1, y=1

When x=2, y=1/4

When x=3, y=1/9

You might be interested in

storchak [24]

Answer:

We let x 1 = 13, y 1 = 8, x 2 = 9, y 2 = 6, x 3 = 4, y 3 = 2, x 4 = 8, y 4 = 4 and the area is given by The absolute value of the cross product of two vectors a →, b → ∈ R 3 spanning the parallelogram is its area:

Step-by-step explanation:

7 0

3 years ago

what is the vertical change shown on the graph? give the answer as a decimal rounded to the nearest tenth, if necessary

Savatey [412]

Answer:

where is the graph ?

pls tell

8 0

3 years ago

Find the given higher-order derivative.<br><br> f''(x) = 9- 3/x<br><br> f'''(x)=

Genrish500 [490]

Answer:

$f'''(x)=\frac{3}{x^{2}}$

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

$f''(x)=9-\frac{3}{x}$

We need to find Third-order derivative of the function f(x).

$f''(x)=9-\frac{3}{x}=9-3x^{-1}$

We know that,

f'''(x) = (f''(x))'

So,

$f'''(x)=\frac{\mathrm{d}\,f''(x)}{\mathrm{d} x}$

$f'''(x)=\frac{\mathrm{d}\,(9-3x^{-1})}{\mathrm{d} x}$

$f'''(x)=\frac{\mathrm{d}\,9}{\mathrm{d} x}-\frac{\mathrm{d}\,3x^{-1}}{\mathrm{d} x}$

$f'''(x)=0-3\frac{\mathrm{d}\,x^{-1}}{\mathrm{d} x}$

$f'''(x)=-3(-1)x^{-1-1}$

$f'''(x)=3x^{-2}$

$f'''(x)=\frac{3}{x^{2}}$

Therefore, $f'''(x)=\frac{3}{x^{2}}$

4 0

4 years ago

Sam packed some cookies in a right circular cylindrical can which has a radius of 5 inches and its height is 9 inches. What is t

Usimov [2.4K]

140 po hope you get a good grade

6 0

3 years ago

5 ^6 − 5 ^11 = 5 x ( 1 − 5 y ) what is the value of x and y

Eva8 [605]

Is it 5^6 - 5^11 = 5x × (1-5y)?
5^6 - 5^11 = 5^(6-11) = 5^(-5) = 1/(5^5)
So 1/3125 = 5x - 5(5y)
1/3125 = 5(x-5y)
1/3125/5 = x-5y
0.000064 = x - 5y

6 0

3 years ago