Step-by-step explanation:
26 weeks are required hope in right
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>
g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).
Since, it follows from the Fundamental theorem of calculus that given an integral where;
Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);
g'(x) = f(x).
Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:
g'(x) =
= 1
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
Read more on fundamental theorem of calculus;
brainly.com/question/14350153
#SPJ1
(You forgot to provide the choices!?!)
A.) Cos Z = b/c
B.) Sin X= c/b
C.) Tan X = b/a
D.) Tan Z = a/b
B is the answer, Sin X = c/b is wong because Sin X= b/c ( sin = opposite/ hypotenuse)
Hope this helps.!
The answer would be 177.4
Answer:
2
Step-by-step explanation:
The scale factor is 2 because every aspect of figure a doubled.