2 years ago

(7.10; 7.15)

1 answer:

7 0

Answer:

We let x 1 = 13, y 1 = 8, x 2 = 9, y 2 = 6, x 3 = 4, y 3 = 2, x 4 = 8, y 4 = 4 and the area is given by The absolute value of the cross product of two vectors a →, b → ∈ R 3 spanning the parallelogram is its area:

Step-by-step explanation:

You might be interested in

what is the least whole number that has the remainders 10,12, and 15 when divided by 16, 18. and 21, respectively

AnnZ [28]

Answer:

$1002$

Step-by-step explanation:

First find difference between the divisors and remainders.

$16-10=6\\18-12=6\\21-15=6$

Here, the difference between the divisors and remainders is equal.

So, the required number is equal to LCM of $(16,18,21)-6$

$16=2^4\\18=2(3^2)\\21=3(7)$

LCM of $(16,18,21)=2^4(3^2)(7)=1008$

Required Number $=1008-6=1002$

7 0

2 years ago

Find the value of the lesser root of x2 + 12x + 35 = 0.

matrenka [14]

In quadratic equations,
a + b = -B
ab = C
where a and b are the roots, B is the second term, and C is the constant.
Substituting,
a + b = -12
ab = 35
The values of a and b from the equation is -7 and -5. Thus, the lesser root is -7.

8 0

3 years ago

What is 4/6 equal to

timama [110]