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oee [108]
3 years ago
14

Linda is buying boxes of ice cream sandwiches for her class party. She has to decide how many boxes she should purchase. A formu

la for this scenario is: z=ax/y z=number of boxes a=number of bars each student will eat x=number of students at the party y=number of ice-cream bars per box Linda has 24 students in her class and she wants each student to have 3 ice-cream sandwiches. If there are 12 sandwiches in a box, how many boxes should Linda buy?
Mathematics
2 answers:
Inessa [10]3 years ago
7 0
3 x 24 = 72 ice cream sandwiches needed. <span>72 / 12 = 6

</span>
<span>linda will need to buy 6 boxes

-beanz
</span>
Aleksandr-060686 [28]3 years ago
3 0
Z = 2 * 28/ 14
z = 56 / 14
Z = 4
Hope this helps

~HotTwizzlers
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In quadrilateral PQRS below, sides PS and QR are parallel for what value of x ?
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3 years ago
A 99% confidence interval (in inches) for the mean height of a population is 65.7 &lt; μ &lt; 67.3. This result is based on a sa
Wittaler [7]

Answer:

66.5 -1.976* 0.3065= 65.89

66.5 +1.976* 0.3065= 67.11

And the 95% confidence interval would be givne by (65.89; 67.11)

Step-by-step explanation:

For this case we have a 99% confidence interval for the true mean hegiht givne by:

65.7 \leq \mu \leq 67.3

And we can begin finding the mean with this formula:

\bar X= \frac{65.7 +67.3}{2}= 66.5

Now we can estimate the margin of error:

ME = \frac{67.3-65.7}{2}= 0.8

The sample size for this case is n = 144 then the degrees of freedom are given by:

df = n-1= 144-1=143

And then we can find a critical value for a 99% of confidence and 143 degrees of freedom using a significance level of 0.01 and we got:

t_{\alpha/2}= 2.61

Then the standard error is given by:

SE = \frac{ME}{t_{\alpha/2}}= \frac{0.8}{2.61}= 0.3065

Now we can find the other critical value for 95% of confidence and we got:

t_{\alpha/2}= 1.976

And the new confidence interval would be given by:

66.5 -1.976* 0.3065= 65.89

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And the 95% confidence interval would be givne by (65.89; 67.11)

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