All categories

2 years ago

4)Without a calculator, name the zeros and sketch the graph. 56.) = -2x(x-4)^2(x+3)^2

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

6 0

Answer:

0, 4, -3

Step-by-step explanation:

replace y with 0 and then fro the sketch I recommend you tomuse desmos good luck buddie

You might be interested in

Lucy is going to walk in a fundraising event to raise money for her school band. Her mother has agreed to donate $7.50 to the sc

Readme [11.4K]

Answer: y = $7.50x + $25

Step-by-step explanation:

From the question, we are informed that Lucy is going to walk in a fundraising event to raise money for her school band and her mother has agreed to donate $7.50 to the school for each mile that Lucy walks, plus an additional $25.

The equation that represents y, the total amount of money Lucy's mother will donate if Lucy walks x miles during the event will be:

= ($.750 × x) + $25

y = $7.50x + $25

Since Lucy walks x Mike's, we multiply x by $7.50 and then add the answer to the additional $25 which is the answer gotten above.

7 0

3 years ago

A construction worker was covering the bathroom walls with tiles. He covered three-fifths of the wall with 50 tiles. How many ti

Eddi Din [679]

It will take 83 1/3 tiles to fill the wall.

Let x be the entire wall:
3/5x = 50

Divide both sides by 3/5:
x = 50 ÷ 3/5
x = 50/1 ÷ 3/5
x = 50/1 × 5/3
x = 250/3 = 83 1/3

3 0

3 years ago

I need some help with this calculus 1 question.

Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

$y=x-x^5$

The derivative is

$y'=1-5x^4$

(a) The slope of the tangent line at (1,0) is

$f'(1)=1-5\cdot 1^4=-4$

$f'(1)=-4$

(b) The equation of the tangent line can be found with the general formula of the line:

$y-y_o=m(x-x_o)$

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

$y-0=-4(x-1)$

Or, equivalently

$y+4x-4=0$

3 0

2 years ago

The frosty ice cream shop sells sundaes for $2 and banana splits for $3. On a hot day the shoot sold 8 more sundaes than banana

sashaice [31]

Let’s designate the number of banana splits sold as x. That means the number of sundaes sold is x + 8.

Now if we put this into an equation, also keeping in mind their costs, we get:
3(x) + 2(x + 8) = 156

Now to solve for x:
3x + 2(x + 8) = 156
3x + 2x + 16 = 156
5x = 140
x = 28

That means you’ve sold 28 banana splits and 36 sundaes! :)

7 0

3 years ago

What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!

Radda [10]

Two main facts are needed here:

1. The logarithm $\log x$ , regardless of the base of the logarithm, exists for $x>0$ .

2. The square root $\sqrt x$ exists for $x\ge0$ .

(in both cases we're assuming real-valued functions only)

By (2) we know that $\sqrt{2x-1}$ exists if $2x-1\ge0$ , or $x\ge\dfrac12$ .

By (1), we know that $\log(\sqrt{2x-1}+3)$ exists if $\sqrt{2x-1}+3>0$ , or $\sqrt{2x-1}>-3$ . But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require $x\ge\dfrac12$ , so the function has domain $\left[\dfrac12,\infty)$ .

To determine the range, we need to know that, in their respective domains, $\sqrt x$ and $\log x$ increase monotonically without bound. We also know that $x=\dfrac12$ at minimum, at which point the square root term vanishes, so the least value the function takes on is $\log3$ . Then its range would be $[\log3,\infty)$ .

3 0

3 years ago