1 inch= 2.54
6 inch= 15.24 becuase 2.54*6=15.24
Hope this helps!!
Is this it or is there more to this question?
Answer:
5 or less
Step-by-step explanation:
The speed increased linearly with distance, but is not decreasing linearly with distance. This suggests the track has an unknown shape, so prediction of car behavior is a guess, at best.
If the car continues to decrease its speed at 3 units per unit distance, then the final 3 units of speed will decrease to 0 in one additional unit of distance. That is, the car will stop at a distance of 5 units.
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Since the car has be decreasing its speed at an increasing rate with respect to distance, very possibly the car will stop before it reaches distance unit 5.
Since we don't know the track shape, it seems possible the car may not stop until some large unknown number of distance units, say 10 or 1000.
Answer:
152 lies between two consecutive integers 151 and 153.
Step-by-step explanation:
Let n be the given integer.
The predecessor of any integer n is given by n-1.
Similarly the successor of an integer n is given by n+1.
For example: Let n be 100
Then its predecessor is 100-1 = 99
Its successor is 100+1 = 101
In the given question, n=152.
Predecessor of 152 = 152 - 1 = 151
Successor of 152 = 152 + 1 = 153
So 152 lies between two successive integers 151 and 153.
Answer:
6,000 meters
Step-by-step explanation:
Length of one lap d = 400 m
Lee's speed = u = 7.2 km/h. Shelby's speed v = 9 km/h
After time t, Shelby will run x meters to cover exactly 3 more laps than Lee.
So x = vt
and
x - 3d = ut
Note t = x/v, then
x - 3d = x*u/v
x (1 - u/v) = 3d
x = 3d/(1 - u/v) = 3*400/(1 - 7.2/9) = 6,000 meters