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hodyreva [135]
3 years ago
8

Networking is the most effective search method for finding job leads. a. True b. False

Computers and Technology
2 answers:
kogti [31]3 years ago
8 0

Answer:

Its true just took the test

Explanation:

natima [27]3 years ago
3 0
True.
This is due to most companies having online websites in our era
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include iPods, PlayStations, Xbox, TiVo, and WRT54G.

Explanation:

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Design a class that has an array of floating-point numbers. The constructor should accept an integer argument and dynamically al
attashe74 [19]

Answer:

See explaination for the code

Explanation:

Here is the code

class NumberArray

{

private:

float *aptr; // Pointer to the array

int arraySize; // Holds the array size

float max,min,avg;

public:

NumberArray(int); // Constructor

~NumberArray(); // Destructor

int size() const // Returns the array size

{ return arraySize; }

void storeNumber(float num,int ele);

float retrieveNumber(int ele);

float getHighest();

float getLowest();

float getAverage();

};

//*******************************************************

// Constructor for IntArray class. Sets the size of the *

// array and allocates memory for it. *

//*******************************************************

NumberArray::NumberArray(int s)

{

arraySize = s;

aptr = new float [s];

for (int count = 0; count < arraySize; count++)

*(aptr + count) = 0;

}

//******************************************************

// Destructor for IntArray class. *

//******************************************************

NumberArray::~NumberArray()

{

if (arraySize > 0)

delete [] aptr;

}

void NumberArray::storeNumber(float num,int ele)

{

if(ele<arraySize)

*(aptr+ele)=num;

}

float NumberArray::retrieveNumber(int ele)

{

return *(aptr+ele);

}

float NumberArray::getHighest()

{

float high=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(high<*(aptr+i))

high=*(aptr+i);

return high;

}

float NumberArray::getLowest()

{

float low=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(low>*(aptr+i))

low=*(aptr+i);

return low;

}

float NumberArray:: getAverage()

{

float ag=0;

for(int i=1;i<arraySize;i++)

ag+=*(aptr+i);

ag=ag/arraySize;

return ag;

}

//Header file section

#include <iostream>

using namespace std;

int main()

{

const int SIZE = 10; // Array size

// Define an IntArray with 10 elements.

NumberArray table(SIZE);

//function call to store values

table.storeNumber(1,0);

table.storeNumber(3,1);

table.storeNumber(7,2);

table.storeNumber(2,3);

//display values

cout<<"Highest value:"<<table.getHighest()<<endl;

cout<<"Lowest Value:"<<table.getLowest()<<endl;

cout<<"Average:"<<table.getAverage()<<endl;

///pause system for a while

system("pause");

return 0;

}

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3 years ago
What symbol precedes all structured references in formula autocomplete lists?
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Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If user
Sedbober [7]

Answer:

Replace /* Your solution goes here */ with:

cin>>matchValue;

numMatches = 0;

for (i = 0; i < userValues.size(); ++i) {

if(matchValue == userValues.at(i))

{

numMatches++;

}

}

Explanation:

This line gets input for matchValue

<em>cin>>matchValue; </em>

This line initializes numMatches to 0

<em>numMatches = 0; </em>

The following iteration checks for the number of matches (numMatches) of the matchValue

<em>for (i = 0; i < userValues.size(); ++i) { </em>

<em>if(matchValue == userValues.at(i)) </em>

<em>{ </em>

<em> numMatches++; </em>

<em>} </em>

<em>} </em>

<em>See Attachment for full source code</em>

Download cpp
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Define the terms candidate key and primary key. Explain the difference between a primary key and a candidate key.
Shkiper50 [21]

Explanation:

Both Primary Key and Candidate Key are the attributes that are used to access tuples from a table. These (Primary key and Candidate key) are also can be used to create a relationship between two tables.

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<em> The main difference between them is that a primary key is unique but there can be many candidate keys. </em>

I hope you find this information useful and interesting! Good luck!

5 0
4 years ago
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