Answer:
- def calcSum(d):
- sum = 0
- for x in d:
- sum += int(x)
- return sum
-
- digits = input("Please enter your digits: ")
- print(calcSum(digits))
Explanation:
The solution code is written in Python.
Firstly, create a function that take one input digit string (Line 1).
In the function, create a sum variable with initial value 0.
Use a for loop to traverse through each character in the digit string and in the loop use int method to convert each character to integer and add it to sum variable (Line 3-5) and return the sum as output.
Next, use input function to prompt user enter a digit string (Line 7).
Lastly test the function by passing the input digit as argument and print the result (Line 8).
Hello <span>Abigailguzman6347</span><span>
</span>Answer: If you use a surrogate key, you must ensure that the candidate key of the entity in question performs properly through the use of "unique index" and "not null" constraints.
Hope This Helps!
-Chris
Answer:
void countUp(int num)
{
if(num==0) //base case.
return;
countUp(num-1);//Recursive call.
cout<<num<<" "; //printing the number.
}
for input num=25
Output:-1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
Explanation:
I have used recursion to print the numbers the function is in c++ language.In every recursive call we are decreasing num by 1.As the base case is reached.Then it will backtrack from 1 to num and then we are printing while backtracking.
Answer:
it stores the largest value in list (the maximum) in foo
Explanation:
Initially foo is assigned as the first element of the list
Inside the loop, every element in the list will be compared with foo, starting from the second element. If an element is greater than foo, the new value of the foo will be that element. At the end of the loop, foo will be equal to the largest element in the list.
Answer:
You use parentheses around the data values.
Explanation:
j took the test on edge
