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aev [14]
4 years ago
8

Discuss the differences between a quantitative and qualitative risk analysis. Please write two paragraphs.

Computers and Technology
1 answer:
Burka [1]4 years ago
8 0

Answer:We start each project to get some business benefits. We design it to achieve users and other stakeholder’s satisfaction. And we build it to improve organization KPIs. But, we live in a world where the project faces many uncertainties. These uncertainties or risks can prevent from achieving our project goals or objectives. So, it is critical that we identify them in time to take care of their effective responses.

The more we know our risks, the more we can evaluate and prioritize them timely for:

Reducing their probable negative impacts, or

Increase their likely positive impacts

We can use Qualitative Risk Analysis and Quantitative Risk Analysis techniques to evaluate and prioritize risks. I see there are a lot of confusions around how these two techniques are different from each other.  In this blog, I will address these confusions and differences between these two techniques.

Before we get into the difference between qualitative and quantitative risk analysis/assessment, it is mandatory to understand how we perform risk analysis in projects.  Below is the summarized demonstration of the risk analysis:

Explanation:

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Develop a CPP program to test is an array conforms heap ordered binary tree. This program read data from cin (console) and gives
mafiozo [28]

Answer:

Following are the code to this question:

#include<iostream>//import header file

using namespace std;

int main()//defining main method

{

int ar[7];//defining 1_D array that stores value      

int i,x=0,l1=1,j; //defining integer variable

for(i=0;i<7;i++)//defining for loop for input value from user ends  

{

cout<<"Enter a Number: ";//print message

cin>>ar[i];//input value in array

if(l1<=2 && i>0)//using if block that checks the array values  

{

x++;//increment the value of x by 1  

}

if(l1>2 && i>0)//using if block that checks the array values  

{

l1=l1-2;//using l1 variable that decrases the l1 value by 2  

}

j=i-x;//using j variable that holds the index of the root of the subtree

if(i>0 && ar[j]>ar[i])// use if block that checks heap condition  

{

l1++; //increment the value of l1 variable

}

if(i>0 && ar[j]<ar[i])// using the if block that violate the heap rule  

{

cout<<ar[i]<<" "<<"Violate the heap";//print message with value

break;//using break keyword  

}

}

return 0;

}

Output:

1)

Enter a Number: -15

Enter a Number: -5

-5 Violate the heap

2)

Enter a Number: 45

Enter a Number: 0

Enter a Number: 55

55 Violate the heap

Explanation:

  • In the above-given C++ language code, an array "ar" and other integer variables " i,x,l1, j" is declared, in which "i" variable used in the loop for input values from the user end.
  • In this loop two, if block is defined, that checks the array values and in the first, if the block it will increment the value of x, and in the second if the block, it will decrease the l1 value by 2.
  • In the next step, j variable is used that is the index of the root of the subtree. In the next step, another if block is used, that checks heap condition, that increment the value of l1 variable. In the, if block it violate the heap rule and print its values.
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Write a program that calculates the average rainfall for three months. The program should ask the user to enter the name of each
sergeinik [125]

Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // string array

   string m[3];

   // array to store rainfall

   double rainfall[3];

   // variables

   double avg_rainfall,sum=0;

   

   for(int i=0;i<3;i++)

   {

       cout<<"Enter name of month "<<i+1<<" :";

       // read month name

       cin>>m[i];

       cout<<"Enter rainfall (inches)  in month "<<i+1<<" :";

       // read rainfall

       cin>>rainfall[i];

       // sum of rainfall

       sum+=rainfall[i];

   }

   // Average rainfall

   avg_rainfall=sum/3;

   // print Average rainfall

   cout<<"Average rainfall for "<<m[0]<<","<<m[1]<<","<<m[2]<<" is "<<avg_rainfall<<" inches."<<endl;

return 0;

}

Explanation:

Create string array "m" to store name of month and double array "rainfall" to store rainfall. Read name of 3 months and rainfall in that month.Find the sum of all the rainfall  and the average rainfall.Print the average rainfall of 3 months.

Output:

Enter rainfall (inches)  in month 2 :45                                                                                    

Enter name of month 3 :july                                                                                                

Enter rainfall (inches)  in month 3 :43                                                                                    

Average rainfall for may,june,july is 42.6667 inches.

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Divide Rs60 in the ratio 1:4​
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Answer on the attachment

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