Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
Marina and Rita’s Cupcakes use the IMAP email protocol. It
is important since it stores copies of all the emails stored on the server.
To add, IMAP<span> (Internet Message Access Protocol) is a standard email
protocol that stores email messages on a mail server, but allows the end user
to view and manipulate the messages,</span>
It's E) both A and B
A) Control logic is invoked
B) Data flow paths are established
Answer:
two
Explanation:
A linked list is a data structure which stores the multiple-element with data type
and a pointer that stores the address of the next element.
A linked list is a series of nodes connecting each other by a pointer.
a node contains data and a pointer.
For build an array, two pointers are used:
the first pointer for specifies the starting node called head node.
and the second pointer is used to connect the other node to build the linked list.
Both are used to build the array if we lose the head node we cannot apply the operation because we do not know the starting node and we cannot traverse the whole linked list.
for example:
1->2->3->4->5
here, 1 is the head node and -> denote the link which makes by the second pointer.
