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Ivahew [28]
2 years ago
8

43 tens × 3 tens = how many hundreds

Mathematics
2 answers:
ladessa [460]2 years ago
4 0
43 tens = 43 * 10 = 430
3 tens = 3 * 10 = 30

430 x 30 = 12900 tens
12900/100 = 129 hundreds <===
pogonyaev2 years ago
4 0
The hundreds are 400
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state which basic Property of addition or multiplication justifies truth of the mathematical expressions 0+7y+2=7y+2
dlinn [17]
The given equation is:

0 + 7y + 2 = 7y + 2

This equation is showing that addition of 0 leaves the expression unchanged. 0 is known as the Additive Identity this means if we add or subtract 0 from any expression, number or equation the result won't be changed.

Therefore, the equation satisfied the property of Additive Identity of Real Numbers.  
8 0
3 years ago
Solve the given system by the substitution method. <br>3x + y = 14 <br>7x - 4y = 20​
Eva8 [605]

Answer:

(4, 2 )

Step-by-step explanation:

Given the 2 equations

3x + y = 14 → (1)

7x - 4y = 20 → (2)

Rearrange (1) making y the subject by subtracting 3x from both sides

y = 14 - 3x → (3)

Substitute y = 14 - 3x into (2)

7x - 4(14 - 3x) = 20 ← distribute parenthesis and simplify left side

7x - 56 + 12x = 20

19x - 56 = 20 ( add 56 to both sides )

19x = 76 ( divide both sides by 19 )

x = 4

Substitute x = 4 into (3) for corresponding value of y

y = 14 - 3(4) = 14 - 12 = 2

solution is (4, 2 )

8 0
2 years ago
Read 2 more answers
Solve 5x3/4 as a mixed number, plz
lana [24]
Multiply straight across
5/1 * 3/4 = 15/4
now change it into a mixed number
3 3/4


4 0
3 years ago
Thats the horizontal distance between (-7,-4) (12,-4)
Svetradugi [14.3K]
The answer is 20.6 hope this helps
7 0
3 years ago
the volume of the a sphere whoes diameter is 18 cm is cubic cm . if it's diameter were reduced by half, it's volume would be of
FrozenT [24]

Answer:

The new volume is 8 times smaller than the original volume

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x ----> the volume of the reduced sphere

y ----> the volume of the original sphere

so

z^{3}=\frac{x}{y}

we have

z=1/2 ----> scale factor

substitute

(1/2)^{3}=\frac{x}{y}

(1/8)=\frac{x}{y}

x=\frac{y}{8}

therefore

The new volume is 8 times smaller than the original volume

Verify

The volume of the original sphere is

r=18/2=9\ cm ---> the radius is half the diameter

V=\frac{4}{3}\pi (9)^{3}=972\pi \ cm^{3}

the volume of the reduced sphere is

r=9/2=4.5\ cm ---> the radius is half the diameter

V=\frac{4}{3}\pi (4.5)^{3}=121.5\pi \ cm^{3}

Divide the volumes

972\pi \ cm^{3}/121.5\pi \ cm^{3}=8

4 0
3 years ago
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