You can tell before you divide 387 by 4, that the first digit of the qoutient is going to be in tens place, because 3 can't go into 4.
Answer:
The distance between the base of the tree and the flower is 9m
Step-by-step explanation:
Here, we have to paint a picture.
The flower is on the ground, the height of the tree is 12m.
The distance from the nest to the flower on the floor is 15m
Indisputably, what we have is a right angled triangle, with the height being 12m, the length of the hypotenuse being 15 and we are asked to calculate the adjacent which represents the distance from the base of the tree to the flower
To get this distance, we simply apply the Pythagoras’ theorem which states that the square of the hypotenuse(longest side of the triangle) is equal to the sum of the squares of the other two sides.
Thus mathematically, we know that our hypotenuse is 15m and the height is 12m
The length we are to calculate is the adjacent and it is equal to;
15^2 - 12^2
= 225 - 144
= 81
The length is thus
√(81) = 9m
Please check attachment for a diagrammatic picture of the triangle
Since one knot is 1.15 mph.
We multiply 35 time 1.15, which equals 40.25 mph.
Then we subtract. 175 - 4.25 = 134.75
Round, and you'll get 135mph
Therefore, your answer is 135mph
Answer:
The towel bar should be placed at a distance of
from each edge of the door.
Step-by-step explanation:
Given:
Length of the towel bar = 
Now given length is in mixed fraction we will convert in fraction.
To Convert mixed fraction into fraction Multiply the whole number part by the fraction's denominator, then Add that to the numerator, then write the result on top of the denominator.
can be Rewritten as 
Length of the towel bar = 
Length of the door = 
can be Rewritten as 
Length of the door = 
We need to find the distance bar should be place at from each edge of the door.
Solution:
Let the distance of bar from each edge of the door be 'x'.
So as we placed the towel bar in the center of the door it divides into two i.e. '2x'
Now we can say that;

Now we will take LCM to make the denominators common we get;

Now denominators are common so we will solve the numerators.

Or 
Hence The towel bar should be placed at a distance of
from each edge of the door.