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Kaylis [27]
3 years ago
7

Solve x2 + 9x + 8 = 0 by completing the square. What are the solutions?

Mathematics
1 answer:
solmaris [256]3 years ago
8 0
Answer: (-1,-8)

Explanation:

x^2 + 9x + 8 = 0
x^2 + 9x = -8

Add (9/2)^2 to both sides

x^2 + 9x + (9/2)^2 = -8 + (9/2)^2
(x + 9/2)^2 = -8 + 81/4
(x + 9/2)^2 = -32/4 + 81/4
(x + 9/2)^2 = 49/4

Square root both sides

Sqrt (x + 9/2)^2 = sqrt 49/4
x + 9/2 = plus or minus 7/2

Set x + 9/2 = 7/2:

x + 9/2 = 7/2
x = 7/2 - 9/2
x = -2/2 = -1

Set x + 9/2 = -7/2:
x + 9/2 = -7/2
x = -7/2 - 9/2
x = -16/2 = -8
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Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector =\frac{\theta}{360}X\pi R^2

Area of the smaller sector =\frac{\theta}{360}X\pi r^2

Area of shaded part =Area of the larger sector-Area of the smaller sector

=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)

From the diagram, R=10 Inch, r=10-7=3 Inch, \theta=95^\circ

Therefore, Area of the sector cleaned

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3 years ago
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