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Lerok [7]
3 years ago
13

Three students need to produce a prime factorization of 48. Donna states that the first factors in the tree should be 6 and 8. L

arry states that the first factors in the tree should be 4 and 12. Trish states that the initial factors of 48 do not affect the prime factorization. Explain why Trish is correct. (HELP ME)
Mathematics
2 answers:
blsea [12.9K]3 years ago
4 0

Answer:

Trish is right because i doesn't matter. It eventually simplifies down to 2x2x2x2x3. What ever path u take it will significantly simplify to that so that is correct.

Hope this helps plz hit the crown :D

Irina18 [472]3 years ago
3 0

Answer:

If we start with 6 and 8, we can break 6 up into 2*3 and 8 into 2*2*2, thus getting a prime factorization of 2*2*2*2*3, or 2^4 *3.

If we begin with 4 and 12, 4 breaks into 2*2 and 12 into 2*2*3, so the prime factorization of 48 is still 2^4 *3.

The starting factors do not matter, since the answer comes out to be the same. There is exactly one correct answer- it doesn't matter how it's found.

Hope this helps! :)

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If d is the midpoint of the segment AC
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Based on the statement below,  if d is the midpoint of the segment AC, the  length of the segment AB  is  4.5cm.

<h3>What is the line segment about?</h3>

in the question given,

AC = 3cm,

Therefore,  AD and DC will be = 1.5cm segments each.  

We are given C as the midpoint of segment DB.

So CB = 1.5cm.

The representation of the line segment is:

A-----------D------------C-------------B

     1.5           1.5            1.5

Since AD, DC and CB are each 1.5cm segments. Then the equation will be:

= 1.5 + 1.5 + 1.5

= 4.5

Therefore, The length of the segment AB is 4.5cm.

See full question below

If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm.

Learn more about midpoint  from

brainly.com/question/10100714

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3 0
2 years ago
In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is
zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

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Answer:

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