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3 years ago

What is the equation of a circle with the center (2,3) and radius 3

Mathematics

1 answer:

ruslelena [56]3 years ago

4 0

Answer:

(x - 2)² + (y - 3)² = 9

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (2, 3) and r = 3, hence

(x - 2)² + (y - 3)² = 9 ← equation of circle

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ohaa [14]

7.50*4=30
40*4=160
160-30=130
130\4=32.5
so each boy has left 32.5 with him

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3 years ago

Shipping costs $0.15 per cubic inch. How much will Marcia pay to ship the box? * A.$20 B.$30 C.$40 D.$50

julia-pushkina [17]

Answer:

5×4= 20

20×10= 200

200×0.15 = 30

B. $30

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3 years ago

I need help with numbers 1 and 2

Snowcat [4.5K]

Answer:

1.No, 143 is not a prime number. The list of all positive divisors the list of all integers that divide 143 is as follows: 1, 11, 13, 143. To be 143 a prime number, it would have been required that 143 has only two divisors, itself and 1.

2.Since the polynomial can be factored, it is not prime.

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3 years ago

Lisa, Juan and isaac equally shared 1/2 of a cake which fraction of the whole cake did each of them recieve

IgorLugansk [536]

Answer:

Each will receive $\frac{1}{6}th$ of the cake.

Step-by-step explanation:

Let the amount of cake = c

Lisa, Juan and Isaac are the persons who are sharing half of a cake equally.

Number of persons = 3

Part of the cake shared = $\frac{c}{2}$

Fraction of the cake shared by each = $\frac{\text{Amount of cake shared}}{\text{Number of persons who shared}}$

= $\frac{\frac{1}{2}c}{3}$

= $\frac{1}{6}c$

Therefore, fraction of total cake shared by each member will be $\frac{1}{6}$ of the total amount of cake.

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2 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

6 0

2 years ago