Coin 1 is Q, the very top coin is N and the one below that is Q. For the bottom coin 2 that's N and the very bottom is also N and the one on top of the very bottom is Q. I hope that helped!
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Answer:
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone ≈ 12.57 m²
Step-by-step explanation:
The given parameters are;
The height of the cone = 5 m
The base radius of the cone = 2 m
The angle which the A
C = 120°
Therefore, we have;
The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone
The angle between [CF] and the base of the cone = tan⁻¹(5/2) = tan⁻¹(2.5) ≈ 68.2°
∴ The angle between [A_F] and the base of the cone = The angle between [CF] and the base of the cone = 68.2°
The angle between [A_F] and the base of the cone = 68.2°
The area of the base of the cone = π × r² = π × 2² = 4·π ≈ 12.57
The area of the base of the cone ≈ 12.57 m².
go down to (0, -9) on the graph, from there go up four and over one and plot the next point, up four over one again, and repeat
Answer:
Step-by-step explanation:
A. 40
B. 28
C. 44
D. 25
200,000 milligrams is the correct answer