Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
N/4.3 = 9.4
4.3 × n/4 = 9.4 × 4.3
n = 40.42
Answer:
1000
Step-by-step explanation:
I search it it cam in a calculator
Answer:
Step-by-step explanation:
Given that:
x + 4y = 30
x - 2y = 0
Subtracting both equations:
6y = 30
y = 30/6
y = 5
Putting in above equation
x + 4(5) = 30
x + 20 = 30
x = 10
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Answer:
(D) 29.3
Step-by-step explanation:
The answer is all the days added together and then divided by 10.
20+30+40+38+25+22+39+22+26+31=293.
293/10=29.3