Answer:
Answered below.
Explanation:
The three general methods consist of unicasting, broadcasting and multicasting.
Casting implies the transfer of data from one computer (sender) to another (recipient).
Unicasting is the transfer of data from a single sender to a single recipient.
Broadcasting deals with the transfer of data from one sender to many recipients.
Multicasting defines the transfer of data from more than one sender to more than one recipients.
Answer:
It is A: Packet metadata is used to route and reassemble information travelling through the internet.
Explanation:
Step 1: The Internet works by chopping data into chunks called packets. Each packet then moves through the network in a series of hops. Each packet hops to a local Internet service provider (ISP), a company that offers access to the network -- usually for a fee
Step 2: Entering the network
Each packet hops to a local Internet service provider (ISP), a company that offers access to the network -- usually for a fee.
Step 3: Taking flight
The next hop delivers the packet to a long-haul provider, one of the airlines of cyberspace that quickly carrying data across the world.
Step 4: BGP
These providers use the Border Gateway Protocol to find a route across the many individual networks that together form the Internet.
Step 5: Finding a route
This journey often takes several more hops, which are plotted out one by one as the data packet moves across the Internet.
Step 6: Bad information
For the system to work properly, the BGP information shared among routers cannot contain lies or errors that might cause a packet to go off track – or get lost altogether.
Last step: Arrival
The final hop takes a packet to the recipient, which reassembles all of the packets into a coherent message. A separate message goes back through the network confirming successful delivery.
Answer:
Consider the language defined by the following regular expression. (x*y | zy*)* 1. Does zyyxz belong to the language?
O. No, because zyy does not belong to x*y nor zy*
2. Does zyyzy belong to the language?
Yes, because both zy and zyy belong to zy*.
Explanation:
