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kati45 [8]
3 years ago
8

Write out code for a nested if statement that allows a user to enter in a product name, store the product into a variable called

product_name and checks to see if that product exists in your nested if statement. You must include 5 product names to search for. If it is then assign the price of the item to a variable called amount and then print the product name and the cost of the product to the console. If it does not find any of the items in the nested if statement, then print that item cannot be found.
Computers and Technology
1 answer:
OlgaM077 [116]3 years ago
6 0

Answer:

product_name = input("Enter product name : ")

if product_name=="pen"or"book"or"box"or"pencil"or"eraser":

   if product_name == "pen":  

       amount = 10

       print(f"Product Name: {product_name}\nCost: {amount} rupees")

   if product_name == "book":

       amount = 100

       print(f"Product Name: {product_name}\nCost: {amount} rupees")

   if product_name == "box":  

       amount = 150

       print(f"Product Name: {product_name}\nCost: {amount} rupees")

   if product_name == "pencil":  

       amount = 5

       print(f"Product Name: {product_name}\nCost: {amount} rupees")

   if product_name == "eraser":

       amount = 8

       print(f"Product Name: {product_name}\nCost: {amount} rupees")

else:  

   print("Item not found!")

Explanation:

The python program is a code of nested if-statements that compares the input string to five items of the first if-statement. For every item found, its code block is executed.

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[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

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Answer:

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\huge\underline\color{brown}\boxed{☕ANSWER:☕}

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b) creating a folder

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d) creating a shortcut

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a) macros

b) relative cell reference

c) absolute cell reference

✒<u> d) mix cell references</u>

3. Which of the following is not a type of lcon

a) program icon

✒ <u>b) document icon </u>

c) folder icon

d) utility icon

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\normalsize\underline\color{yellow}\boxed{TheQuestionner}

\large\mathbb\color{orange}{Correct \: me \: if \: im \: wrong}

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Why is Net WPM a better formula than Gross WPM to calculate typing speed?
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