Answer:
#include<iostream>
#include <vector>
#include <list>
using namespace std;
int main(){
int a[10]={0,1,2,3, 4, 5, 6, 7, 8, 9 };
std::vector<int> v (&a[0],&a[0]+10);
std::list<int> l (&a[0],&a[0]+10);
int b[10];
for(int i=0;i<10;i++){
b[i]=a[i];
}
std::vector<int> v2(v);
std::list<int> l2(l);
for(int i=0;i<10;i++){
b[i]+=2;
}
for(int i=0;i<10;i++){
v2[i]+=3;
}
for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)
*it=*it+5;
cout<<"Each containers value are: "<<endl;
cout<<"1st array: "<<endl;
for(int i=0;i<10;i++){
cout<<a[i]<<" ";
}
cout<<"\n 1st vector: \n";
for(int i=0;i<10;i++){
cout<<v[i]<<" ";
}
cout<<"\n 1st List is:\n";
for (std::list<int>::iterator it = l.begin(); it != l.end(); it++)
cout << *it << ' ';
cout<<"\n 2nd array: "<<endl;
for(int i=0;i<10;i++){
cout<<b[i]<<" ";
}
cout<<"\n 2nd vector:\n";
for(int i=0;i<10;i++){
cout<<v2[i]<<" ";
}
cout<<"\n 2nd list:\n";
for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)
cout << *it << ' ';
return 0;
}
Explanation:
- Initialize an array, a vector and a list of type integer
.
- Create a 2nd array, vector, and list as a copy of the first array, vector, and list.
- Increase the value of each element in the array by 2
, vector by 3 and list by 5.
- Finally display the relevant results.
Well if you add it up , if one cup of coffe is $1, then in one year it would be $365 on coffe.
Answer: <span>Humans do change their response criterion, but more slowly than they should.</span>
<span>B. locate Web pages related to a specific subject.
Not A because currently no search engine has an in-built option to talk to other people, and even if it did it wouldn't be it's core functionality.
Not C, as there is no way to change ISP (internet service provider) using your search engine.
Not D as search engines have no connection to MS Word.</span>
Most answers here focus on installing MySQldb library, I would really suggest opting for MySQl connector/python providing by MySQL/Oracle ,which makes the process much simpler.