Answer:
1) 2 bits 2) shown in explanation 3) shown in explanation 4) 22 bits per pixel (2.75 bytes)
Explanation:
As a bit is one of two states, 1 or 0, 2 bits is sufficient to represent 4 colors:
00 = color 1
01 = color 2,
10 = color 3,
11 = color 4
This would be the custom type of encoding for that specific image as it only uses 4 colors.
Now to calculate the amount of memory saved, which is quite simple:
24-2=22
So you Would save 22 bits per pixel or 2.75 bytes per pixel.
Answer:
All flags are On ( c, z , N )
Explanation:
Given data:
4-bit operation
Assuming 2's complement representation
<u>Determine status flags that are on after performing </u> 1010+0110
1 1
1 0 1 0
0 1 1 0
1 0 0 0 0
we will carry bit = 1 over
hence C = 1
given that: carry in = carry out there will be zero ( 0 ) overflow
hence V = 0
also Z = 1
But the most significant bit is N = 1
Thank you for being the rare question where you actually provide what language you want your answer in; I approve, and encourage this.
In Java, the following will work.
I made it a bit more versatile to work with others numbers, other than 99, if you so please (if not, just hardcode the 99 in yourself).
// Example list - fill this with numbers yourself.
ArrayList<Integer> nums = new ArrayList<>();
int n = 99;
int count = (int)nums.stream().filter(i -> i == n).count();
System.out.println(n + " occurences.");
Enviromental technology can be listed from simple objects to a large company.
1.Enviromental Technology:
Wood farming (its not that of a technology, but the amount technology to do this is large)
2.Coal Mining
3. Water damps (for making electricity)
alright.. good:
1. other objects can be created thanks to this
2. The final product can be used as a source of energy.
3. Electricity!!
the bad.
1. mass-cutting trees... :(
2. Often makes no to some pollution, can have pernament effect on the workers life (respiratory problems etc.)
3. Can cause floods..
Answer:
Python file with appropriate comments given below
Explanation:
#Take the input file name
filename=input('Enter the input file name: ')
#Open the input file
inputFile = open(filename,"r+")
#Define the dictionary.
list={}
#Read and split the file using for loop
for word in inputFile.read().split():
#Check the word to be or not in file.
if word not in list:
list[word] = 1
#increment by 1
else:
list[word] += 1
#Close the file.
inputFile.close();
#print a line
print();
#The word are sorted as per their ASCII value.
fori in sorted(list):
#print the unique words and their
#frequencies in alphabetical order.
print("{0} {1} ".format(i, list[i]));
