Question

Write a C++ console program to do the following: 1. Define an array of ints with the ten elements { 0, 1,2,3, 4, 5, 6, 7, 8, 9 }. 2. Define a vector with those ten elements. 3. Define a list with those ten elements. 4. Define a second array, vect

Answer 1

Answer:

#include<iostream>

#include <vector>

#include <list>

using namespace std;

int main(){

int a[10]={0,1,2,3, 4, 5, 6, 7, 8, 9 };

std::vector<int> v (&a[0],&a[0]+10);

std::list<int> l (&a[0],&a[0]+10);

int b[10];

for(int i=0;i<10;i++){

b[i]=a[i];

}

std::vector<int> v2(v);

std::list<int> l2(l);

for(int i=0;i<10;i++){

b[i]+=2;

}

for(int i=0;i<10;i++){

v2[i]+=3;

}

for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)

*it=*it+5;

cout<<"Each containers value are: "<<endl;

cout<<"1st array: "<<endl;

for(int i=0;i<10;i++){

cout<<a[i]<<" ";

}

cout<<"\n 1st vector: \n";

for(int i=0;i<10;i++){

cout<<v[i]<<" ";

}

cout<<"\n 1st List is:\n";

for (std::list<int>::iterator it = l.begin(); it != l.end(); it++)

cout << *it << ' ';

cout<<"\n 2nd array: "<<endl;

for(int i=0;i<10;i++){

cout<<b[i]<<" ";

}

cout<<"\n 2nd vector:\n";

for(int i=0;i<10;i++){

cout<<v2[i]<<" ";

}

cout<<"\n 2nd list:\n";

for (std::list<int>::iterator it = l2.begin(); it != l2.end(); it++)

cout << *it << ' ';  

return 0;

}

Explanation:

• Initialize an array, a vector and a list of type integer .
• Create a 2nd array, vector, and list as a copy of the first array, vector, and list.
• Increase the value of each element in the array by 2 , vector by 3 and list by 5.
• Finally display the relevant results.