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Delicious77 [7]
3 years ago
5

Janette bought a portable CD player on sale. The regular price was $100. She was charged $89. a) What percent of the regular pri

ce did Janette pay?
b) What percent of the regular price did she receive
as a discount?
Mathematics
1 answer:
LenKa [72]3 years ago
4 0
Regular price = 100% is $100Discounted price = x% is $89
a)
If Janette pays $89 then the percentage paid compared to the original price is = 89/100 = 89%
b)
She received a discount of (100-89) % = 11%Please press the Thank You button and indicate as best answer if these are the answers you're looking for.<span>
</span>
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grigory [225]

Answer and Step-by-step explanation:

The answer is the last answer choice.

g(x) = -(x + 2)^2 + 1

We don't even have to look at the numbers to tell that this is the correct answer. We look at what is being placed there.

The equation for a transformed function is:

f(x) = a(x-h)^2 + k

a determines the scale of the graph and whether the graph opens up or down.

h determines whether the graph shifts left or right.

k determines whether the graph shifts up or down.

We see that there is a -1 for a, which means the graph will be facing downwards. We see a 2 for where h is, but it really is a -2, and when it becomes a positive after simplifying, the graph will shift to the left.

k is a positive 1, so the graph will be shifted up 1 unit.

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5 0
3 years ago
Read 2 more answers
(a) Use a linear approximation to estimate f(0.9) and f(1.1). f(0.9) ≈ f(1.1) ≈ (b) Are your estimates in part (a) too large or
olasank [31]

Answer:

(Missing part of the question is attached)

L(x)=2x+3

Estimates are too large.

Step-by-step explanation:

Suppose the only information we know about the function is:

f(1)=5

where the graph of its derivative is shown in the attachment

<h3>(a)</h3>

If the function f\\ is differentiable at point x=1 , the tangent line to the graph of f at 1 is given by the equation:

y=f(1) +f'(1)(x-1)

So we call the linear function:

L(x)=f(1) +f'(1)(x-1)

We know the f(1)=5 as it is given in the question, and f'(1)=2 from the graph attached. Substitute in the equation of L(x).

L(x)=5+2(x-1)\\L(x)=5+2x-2\\L(x)=2x+3\\

<h3>(b)</h3>

At x=1,  f'(x) is positive but it is decreasing. However. if we draw the tangent lines, we see that the tangent lines are becoming less steeper, so the tangent lines lie above the curve f. Thus, The estimates are too large.

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2 years ago
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Tju [1.3M]

Answer:

option c is the answer for pic

and for question the answer is

(-274)*(437)

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2 years ago
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