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Kamila [148]
3 years ago
8

Tanner went to the bank and deposited $200 if his final balance was $647 what did he begin with?

Mathematics
1 answer:
Tema [17]3 years ago
4 0

Answer:

$847

Step-by-step explanation:

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A lesson ends at 2:30 it lasts for 55 minutes. when does the lesson starts
ss7ja [257]

Answer: 1:35

Step-by-step explanation:

Just go and hour back from 2:30 and add 5 minutes

5 0
3 years ago
Read 2 more answers
The radius of a circle is 1 foot. What is the area of a sector bounded by a 90 degree arc?
soldi70 [24.7K]

Answer:

The answer is 11/14 ft^2 or pi/4 ft^2

Step-by-step explanation:

The area of the sector bounded by that angle measure will be the area of the circle divided by 4

Area of the circle is;

pi * r^2

so the area here is;

22/7 * 1 * 1 = 22/7

divide this by 4

= 22/28 = 11/14 ft^2

8 0
3 years ago
A circle has a radius of 6 cm. What is the area of the circle? (Use 3.14 for pi)
vampirchik [111]

Answer:

113.04 cm²

Step-by-step explanation:

area of a circle= πr²

= 3.14 x 6²

=3.14 x 36

= 113.04 cm²

5 0
3 years ago
Lillianne made 6 out of every 10 baskets she attempted during basketball practice. If she attempted to make 25 baskets, how many
patriot [66]

Answer:

15.

Step-by-step explanation:

(6/ 10) * 25

= 0.6 * 25

= 15.

3 0
3 years ago
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
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