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2 years ago

9

Prem earns Rs. 16000 a month. He spends half of his income on food, three - tenth of the remaining income on house rent and Rs.

2050 on education of his son. How much money is left with him?

1 answer:

Ilia_Sergeevich [38]2 years ago

7 0

Answer:

none because he is broke

Step-by-step explanation:

You might be interested in

How many bricks are left over if you place 213,854 bricks in groups of 10,000?

Monica [59]

This is dividing 213854 by 100000 but instead of giving a decimal you want to give a remainder.

213854/100000 is 2.13854. So you have 2 units, which is 200000.
Subtract 200000 from 213854 and you're left with 13854 bricks that remain.

7 0

3 years ago

Given the functions f(n) = 500 and g(n) = (nine tenths)n − 1, combine them to create a geometric sequence, an, and solve for the

masya89 [10]

Answer:

$A(n) = 500 * (\frac{9}{10})^{n-1$

$A(11) = 174.34$

Step-by-step explanation:

Given

$f(n) = 500$

$g(n) = (\frac{9}{10})^{n-1$

Represent the combination of f(n) and g(n) with A(n)

So, we have:

$A(n) = f(n) * g(n)$

This gives:

$A(n) = 500 * (\frac{9}{10})^{n-1$

To calculate the 11th term, we make use of n = 11

$A(11) = 500 * (\frac{9}{10})^{11-1$

$A(11) = 500 * (\frac{9}{10})^{10$

This gives:

$A(11) = 500 * (0.9)^{10}$

$A(11) = 500 * 0.3486784401$

$A(11) = 174.33922005$

Approximate to 2 dp

$A(11) = 174.34$

3 0

3 years ago

Describe which of the two points lies on the graph of the line<br> Y-x=4<br> A. 9,5<br> B. 5,9

klasskru [66]

B. 5, 9

x = 5
y = 9

y - x = 4

(9) - (5) = 4

True

hope this helps

4 0

3 years ago

How much interest will be paid in 1 year for a loan of $2500 at 9 1/2% simple interest?

raketka [301]

<span>$2,500 * 0.095 = $237.50 in interest for that year.</span>

8 0

3 years ago

Cierra has three more than 1/2 as many purses as Asia defined a variable and write an expression to represent the number of purs

Ray Of Light [21]

Answer:

The equation representing the number of purses Ceirra has is $c=3+\frac{1}{2}\times a$ .

Ceirra has <u>9</u> purses in her collection.

Step-by-step explanation:

Given,

Cierra has three more than 1/2 as many purses as Asia.

Solution,

Let the number of purses Cierra has be 'c'.

And also the number of purses Asia has be 'a'.

Now according to question, Cierra has 3 more than 1/2 purses as Asia has.

Framing in equation form, we get;

$c=3+\frac{1}{2}\times a$

Hence The equation representing the number of purses Ceirra has is $c=3+\frac{1}{2}\times a$ .

Now we solve the equation;

Since Asia has 12 purses.

So we substitute the value of 'a', and get;

$c=3+\frac{1}{2}\times12=3+6=9$

Hence Ceirra has <u>9</u> purses in her collection.

6 0

3 years ago