<h3>Given :-</h3>
- Perimeter of triangle = 42
- Side 1 of triangle = (x + 4)
- Side 2 of triangle = (3x + 8)
- Side 3 of triangle = (5x + 6)
<h3>To find:-</h3>
<h3>Explanation:</h3>
So to find length of sides we have to find the value of x.We can find value of x , by this formula:



So:-






















- Side 1 of triangle = (x + 4)
- Side 1 of triangle =2.67 + 4
- Side 1 of triangle = 6.67
- Side 2 of triangle = 3x + 8
- Side 2 of triangle = 3 × 6.67 + 8
- Side 2 of triangle = 20.01 + 8
- Side 2 of triangle = 28.01
- Side 3 of triangle = 5x + 6
- Side 3 of triangle = 5 × 2.67 + 6
- Side 3 of triangle = 13.35 + 6
- Side 3 of triangle = 19.35
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~WindyMint
Simplify. Note the equal sign. What you do to one side, you do to the other. Follow PEMDAS.
Isolate the x.
First, distribute 6 to all terms within the parenthesis
6(-3) = -18
6(4x) = 24x
7x - 18 + 24x = 199
Simplify. Combine like terms
31x - 18 = 199
Isolate the x. Add 18 to both sides
31x - 18 (+18) = 199 (+18)
31x = 199 + 18
31x = 217
Isolate the x. Divide 31 from both sides
31x/31 = 217/31
x = 217/31
x = 7
7 is your answer for x
hope this helps
Given:
The graph of a function is given.
To find:
The range of the graph.
Solution:
We know that, the domain is the set of input values and range is the set of output values.
In a graph, domain is represented by the x-axis and range is represented by the y-axis.
From the given graph it is clear that there is an open circle at (-8,-8) and a closed circle at (3,4). It means the function is not defined at (-8,-8) but defined for (3,4).
The graph of the function is defined over the interval
. So, the domain is (-8,3].
The values of the function lie in the interval
. So, the range is (-8,4].
Therefore, the range of the function are all real values over the interval (-8,4].
I think the answer is d hope this helps