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3 years ago

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Dave and mary depart from the bus station at 10 am traveling in opposite directions. dave's bus is going 40 miles per hour and m

ary's is going 50 miles per hour. at what time will they be 270 miles apart?

1 answer:

Montano1993 [528]3 years ago

3 0

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During the cold winter months, a sheet of ice covers a lake near the Arctic Circle. At the beginning of spring, the ice starts t

Masja [62]

Answer: The ice sheet's thickness decrease every 6 weeks= 1.5 meters

Step-by-step explanation:

GIven: At the beginning of spring, the ice starts to melt. The variable sss models the ice sheet's thickness (in meters) t weeks after the beginning of spring. $s=-0.25t+4$

At t=0, $s=4$

So, Thickness of ice sheet at the beginning = 4 meters

Now at t= 6, we get

$s=-0.25(6)+4=-1.5+4=2.5$

Thickness of ice sheet after 6 weeks = 2.5 meters

Decrease in thickness = 4 meters - 2.5 meters = 1.5 meters

Hence, the ice sheet's thickness decrease every 6 weeks= 1.5 meters

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3 years ago

Whole Numbers include both positive and negative numbers. t or f

Alex

Answer:

t

Step-by-step explanation:

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3 years ago

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Match each explicit formula to its corresponding recursive formula.

Murrr4er [49]

Answer:

See attached

Step-by-step explanation:

The answer is in below picture

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3 years ago

What is a real world example of a ratio?

almond37 [142]

Answer:

Step-by-step explanation:

You could use the scores of a football game: 13:22 points

Or how many boys and girls are in your class: There are 12 girls to 13 boys, 12:13 or 12/13

Or you could say how many dogs and cats there are in an animal shelter: There are 11 dogs to 24 cats, 11:24, 11 dogs/24 cats

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3 years ago

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36x2 + 49y2 = 1,764 The foci are located at

Vaselesa [24]

Answer:

The foci are located at: $(-\sqrt{13},0)$ and $(\sqrt{13},0)$

Step-by-step explanation:

The given conic has equation: $36x^2+49y^2=1764$

Divide each term by 1764

$\frac{36x^2}{1764}+\frac{49y^2}{1764}=\frac{1764}{1764}$

$\implies \frac{x^2}{49}+\frac{y^2}{36}=1$

$\implies \frac{x^2}{7^2}+\frac{y^2}{6^2}=1$

Comparing to:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$

We have a=7 and b=6

We use the relation $a^2-b^2=c^2$ to find c.

$\implies 7^2-6^2=c^2$

$\implies 49-36=c^2$

$\implies 13=c^2$

$\implies c=\pm \sqrt{13}$

The foci are located at: $(-\sqrt{13},0)$ and $(\sqrt{13},0)$

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3 years ago

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