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il63 [147K]
3 years ago
7

What is this? Someone please help me

Mathematics
1 answer:
Reil [10]3 years ago
8 0

Answer and Step-by-step explanation:

Haven't done this in a while, so here we go:

The rule (I'm not really sure) would have to be negative number and negative number.

This means that:

(4, 0) would become (-4, 0) A'

(6, -2) becomes (-6, 2) B'

(8, -7) becomes (-8, 7) C'

and (0, -5) becomes (0, 5) D'

#teamtrees #WAP (Water And Plant)

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Step-by-step explanation:

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Your birds drink 8 1/3 ounces of water a day. How many ounces of water do they drink in 6 days?​
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Perimeter = (x+2) + x + (x+2) + x
Perimeter = 4x + 4

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)
vagabundo [1.1K]

Answer:

Considering the given equation y = log_{3}x\\

And the ordered pairs in the format (x, y)

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For (\frac{1}{3}, a_{0} )

x=\frac{1}{3}

y=a_{0}

y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1

So the ordered pair will be (\frac{1}{3}, -1 )

For (1, a_{1} )

x=1

y=a_{1}

y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0

So the ordered pair will be (1, 0 )

For (3, a_{2} )

x=3

y=a_{2}

y = log_{3}x\\y = log_{3}3\\y = 1

So the ordered pair will be (3, 1 )

For (9, a_{3} )

x=9

y=a_{3}

y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2

So the ordered pair will be (9, 2 )

For (27, a_{4} )

x=27

y=a_{4}

y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3

So the ordered pair will be (27, 3 )

For (81, a_{5} )

x=81

y=a_{5}

y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4

So the ordered pair will be (81, 4 )

4 0
4 years ago
Please help me on math homework! <br> File attached! :D
r-ruslan [8.4K]
Use pythagorena theorme

D=\sqrt{(x1-x2)^{2}+(y1-y2)^{2}}
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points given are
(1,1)
(5,6)
x1=1
y1=1
x2=5
y2=6
D=\sqrt{(1-5)^{2}+(1-6)^{2}}
D=\sqrt{(-4)^{2}+(-5)^{2}}
D=\sqrt{16+25}
D=\sqrt{41}
6.403


answer is B
7 0
3 years ago
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