I believe the expression would be 7(g)+7
To compare the two classes, the Coefficient of Variation (COV) can be used. The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)
For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)
The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
17. Yes!! SAS theorem
18. Yes !! SSS theorem
19. Yes !! SSS theorem
20. I don’t think so
Answer:
c,d
Step-by-step explanation:
![ab^{-3x}=a(b^{-3})^x=a(\frac{1}{b^3} )^x=a[(\frac{1}{b} )^3]^x\\=a(\frac{1}{b} )^{3x}](https://tex.z-dn.net/?f=ab%5E%7B-3x%7D%3Da%28b%5E%7B-3%7D%29%5Ex%3Da%28%5Cfrac%7B1%7D%7Bb%5E3%7D%20%29%5Ex%3Da%5B%28%5Cfrac%7B1%7D%7Bb%7D%20%29%5E3%5D%5Ex%5C%5C%3Da%28%5Cfrac%7B1%7D%7Bb%7D%20%29%5E%7B3x%7D)
X=number total of student at the school.
70% of x=161
can suggest this equation:
(70/100)x=161
0.7x=161
x=161/0.7=230
Answer: the school has 230 students
