Answer with Step-by-step explanation:
Let F be a field .Suppose and
We have to prove that a has unique multiplicative inverse.
Suppose a has two inverses b and c
Then, where 1 =Multiplicative identity
(cancel a on both sides)
Hence, a has unique multiplicative inverse.
The slope of the line that contains the point (13,-2) and (3,-2) is 0
<em><u>Solution:</u></em>
Given that we have to find the slope of the line
The line contains the point (13,-2) and (3,-2)
<em><u>The slope of line is given as:</u></em>
Where, "m" is the slope of line
Here given points are (13,-2) and (3,-2)
<em><u>Substituting the values in formula, we get,</u></em>
Thus the slope of line is 0
Find m∠BOC, if m∠MOP = 110°.
Answer:
m∠BOC= 40 degrees
Step-by-step explanation:
A diagram has been drawn and attached below.
Since ∠AOD is a straight line
x+x+y+y+z+z=180 degrees
We are given that:
m∠MOP = 110°.
From the diagram
∠MOP=x+2y+z
Therefore:
x+2y+z=110°.
Solving simultaneously by subtraction
x+2y+z=110°.
We obtain:
x+z=70°
Since we are required to find ∠BOC
∠BOC=2y
Therefore from x+2y+z=110° (since x+z=70°)
70+2y=110
2y=110-70
2y=40
Therefore:
m∠BOC= 40 degrees
