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mafiozo [28]
3 years ago
11

Jacob performs the work shown to find tan Tangent 165 degrees. Tangent 165 degrees = negative StartRoot StartFraction 1 + cosine

330 degrees Over 1 minus cosine 330 degrees EndFraction EndRoot = negative StartRoot StartStartFraction 1 + (StartFraction StartRoot 3 EndRoot Over 2 EndFraction) OverOver 1 minus (StartFraction StartRoot 3 EndRoot Over 2 EndFraction) EndEndFraction = negative StartRoot StartStartFraction 2 + StartRoot 3 EndRoot Over 2 EndFraction OverOver StartFraction 2 minus StartRoot 3 EndRoot Over 2 EndFraction EndEndFraction EndRoot Equals negative StartRoot StartFraction 2 + StartRoot 3 EndRoot Over 2 minus StartRoot 3 EndRoot EndFraction EndRoot. Equals negative StartStartRoot 7 + 4 StartRoot 3 EndRoot EndEndRoot. Observe Jacob’s work. Use the drop down box to complete the statement. The error in Jacob’s work is
Mathematics
2 answers:
abruzzese [7]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Troyanec [42]3 years ago
4 0

Answer:

the cosine expressions are reversed

Step-by-step explanation:

edge 2020

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Please if your answering it please i need it step by step please
salantis [7]
I) there are 360 degrees in a circle.  So subtract all the numbers from 360 to get the angle for econ.

That angle is 65 degrees

ii) If 95 degrees represents 228 books, then 360 degrees represents "x" (total) books.  So we have an equation:
<u>95</u> = <u>360</u>
228     x

Solve for x, and we get x = 864

iii) The percentage is 80 degrees out of 360 degrees or 2/9 or roughly 0.222 or 22.2%
4 0
3 years ago
Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6
horsena [70]

Answer:

x^{4} -18x^{3}+104x^{2} -172x-100

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:  

\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))(  x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\

7 0
3 years ago
Select all the rates that correspond to a unit rate of $6 per sandwich. You must select all correct responses to receive credit.
faltersainse [42]

Answer:

B, C, and E

Step-by-step explanation:

A. 42/6 = 7     Not correct

B. 42/7 = 6     Correct

C. 108/18 = 6  Correct

D. 40/5 = 8     Not correct

E. 96/16 = 6     Correct

5 0
3 years ago
Find the slope of the line that passes through the points (0, -3) and (-4,1).
kozerog [31]

The formula for slope is \frac{y_{2} -y_{1} }{x_{2} -x_{1} }

In this case:

y_{2} = 1\\ y_{1} }= -3\\x_{2} = -4\\x_{1} = 0

so...

\frac{1 - (-3)}{-4 - 0}

\frac{4}{-4}

-1 <<<The slope

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0
3 years ago
Read 2 more answers
Which equation is graphed in the diagram​
Dima020 [189]

Answer:

y=1/2x-1

Step-by-step explanation:

4 0
3 years ago
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