Answer:
See below ~
Step-by-step explanation:
Given :
⇒ m∠1 = m∠2
⇒ HD = GF
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To Prove :
<u>Δ EHD ≅ Δ EGF</u>
<u />
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Solving :
⇒ m∠1 = m∠2 (Given)
⇒ HD = GF (Given)
⇒ ∠E = ∠E (Common angle)
⇒ ΔEHD ≅ ΔEGF (AAS congruence)
Given:
x = 12 in, y = 16 in and z = 20 in
To find:
The surface area of the geometric shape.
Solution:
Area of top rectangle = z × z
= 20 × 20
Area of top rectangle = 400 in²
Area of middle rectangle = z × y
= 20 × 16
Area of middle rectangle = 320 in²
Area of bottom rectangle = z × x
= 20 × 12
Area of bottom rectangle = 240 in²
Area of left triangle = 

Area of left triangle = 96 in²
Area of right triangle = 

Area of right triangle = 96 in²
Surface area = 400 + 320 + 240 + 96 + 96
= 1152
The surface area of the geometric shape is 1152 in².
Answer:
1/3
Step-by-step explanation:
<em>Method 1.</em>
slope = rise/run
Rise is vertical distance.
Run is horizontal distance.
Find two points that are easy to read (on grid intersections):
(2, -1) and (5, 0).
Start at (2, 1). You need to go to (5, 0) by moving only vertically and horizontally. Go up 1 unit. That is a rise of 1. Now go right 3 units. That is a run of 3.
rise = 1
run = 3
slope = rise/run = 1/3
<em>Method 2.</em>
Use the slope formula and two points on the line.

Use points (2, -1) and (5, 0).



slope = 1/3
Given:
Slope of line F = 
Slope of line G = 
To find:
The conclusion about distinct lines F and G.
Solution:
We have,
Slope of line F = 
= 
Slope of line G = 
= 
The slopes of lines F and G are equal and we know that the slopes of two parallel lines are always equal.
Therefore, the line F and line G are parallel to each other.
What's the small part on the bottom?