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vampirchik [111]
3 years ago
14

Which expression is equivalent to 15a^8b^4/5a^4b

Mathematics
2 answers:
LekaFEV [45]3 years ago
4 0

Answer: The given expression \frac{15a^8b^4}{5a^4b} simplified to  3a^4b^3

Step-by-step explanation:

Given : expression \frac{15a^8b^4}{5a^4b}

We have to simplify the given expression \frac{15a^8b^4}{5a^4b}

Consider the given expression \frac{15a^8b^4}{5a^4b}

Divide the numbers \frac{15}{5}=3

=\frac{3a^8b^4}{a^4b}

Apply exponent rule, \frac{x^a}{x^b}\:=\:x^{a-b}

We have,

\frac{a^8}{a^4}=a^{8-4}=a^4

=\frac{3a^4b^4}{b}

Cancel out common factor b,

We have

=3a^4b^3

Thus, the given expression \frac{15a^8b^4}{5a^4b} simplified to  3a^4b^3

Sonbull [250]3 years ago
4 0

Answer:

\frac{15a^8b^4}{5a^4b}=3a^{4}b^{3}

Step-by-step explanation:

Given : Expression \frac{15a^8b^4}{5a^4b}

To find : The simplified form of the expression?

Solution :

Step 1 - Write the expression

\frac{15a^8b^4}{5a^4b}

Step - 2 Divide Nr. and Dr. by 5

=\frac{3a^8b^4}{a^4b}

Step 3 - Apply exponent rule i.e, \frac{x^a}{x^b}\:=\:x^{a-b}

=3a^{8-4}b^{4-1}}

=3a^{4}b^{3}

Therefore, The required simplified form of the given expression is

\frac{15a^8b^4}{5a^4b}=3a^{4}b^{3}

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Answer:

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Step-by-step explanation:

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⇒ m∠1 = m∠2

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Solving :

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maria [59]

Given:

x = 12 in, y = 16 in and z = 20 in

To find:

The surface area of the geometric shape.

Solution:

Area of top rectangle = z × z

                                    = 20 × 20

Area of top rectangle = 400 in²

Area of middle rectangle = z × y

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Area of middle rectangle = 320 in²

Area of bottom rectangle = z × x

                                          = 20 × 12

Area of bottom rectangle = 240 in²

Area of left triangle = \frac{1}{2}yx

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Area of left triangle = 96 in²

Area of right triangle = \frac{1}{2}yx

                                $=\frac{1}{2}\times16\times12

Area of right triangle = 96 in²

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3 years ago
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Answer:

1/3

Step-by-step explanation:

<em>Method 1.</em>

slope = rise/run

Rise is vertical distance.

Run is horizontal distance.

Find two points that are easy to read (on grid intersections):

(2, -1) and (5, 0).

Start at (2, 1). You need to go to (5, 0) by moving only vertically and horizontally. Go up 1 unit. That is a rise of 1. Now go right 3 units. That is a run of 3.

rise = 1

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slope = rise/run = 1/3

<em>Method 2.</em>

Use the slope formula and two points on the line.

slope = m = \dfrac{y_2 - y_1}{x_2 - x_1}

Use points (2, -1) and (5, 0).

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The conclusion about distinct lines F and G.

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