Can someone help me out

Mathematics

1 answer:

Effectus [21]3 years ago

7 0

Answer: V=9.4 cm^3

Step-by-step explanation:

$V=\pi r^2h\\V=\pi (1)^2(3)\\V=9.4cm^3$

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A bike store marks up the wholesale cost of all bikes they sell by 30%. calvin wants to buy a bike that has a price log of 123.5

viktelen [127]

The wholesale cost of the bike is 95.

Wholesale price is the price charged for a product as sold in bulk to large trade or distributor groups as opposed to what is charged to consumers.

The selling price is how much a buyer pays for a product or service.

The profit formula is used to calculate the amount of gain that has been made in a transaction

Profit = Selling Price (S.P.) - Cost Price (C.P.)(here it is the wholesale price)

Given =

Selling Price = 123.50
Wholesale price = ?
Profit = 30% of wholesale price

Substituting it in the profit formula we get

0.3 x wholesale price = 123.50 + wholesale price

1.3 x wholesale price = 123.50

Wholesale price = $\frac{123.50}{1.3}$ = 95

Thus the wholesale cost of the bike is 95.

Learn more about profit here :

brainly.com/question/12929999

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6 0

1 year ago

5. Show that the following points are collinear. a) (1, 2), (4, 5), (8,9)

Irina-Kira [14]

Label the points A,B,C

A = (1,2)
B = (4,5)
C = (8,9)

Let's find the distance from A to B, aka find the length of segment AB.

We use the distance formula.

$A = (x_1,y_1) = (1,2) \text{ and } B = (x_2, y_2) = (4,5)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (2-5)^2}\\\\d = \sqrt{(-3)^2 + (-3)^2}\\\\d = \sqrt{9 + 9}\\\\d = \sqrt{18}\\\\d = \sqrt{9*2}\\\\d = \sqrt{9}*\sqrt{2}\\\\d = 3\sqrt{2}\\\\$

Segment AB is exactly $3\sqrt{2}$ units long.

Now let's find the distance from B to C

$B = (x_1,y_1) = (4,5) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(4-8)^2 + (5-9)^2}\\\\d = \sqrt{(-4)^2 + (-4)^2}\\\\d = \sqrt{16 + 16}\\\\d = \sqrt{32}\\\\d = \sqrt{16*2}\\\\d = \sqrt{16}*\sqrt{2}\\\\d = 4\sqrt{2}\\\\$

Segment BC is exactly $4\sqrt{2}$ units long.

Adding these segments gives

$AB+BC = 3\sqrt{2}+4\sqrt{2} = 7\sqrt{2}$

----------------------

Now if A,B,C are collinear then AB+BC should get the length of AC.

AB+BC = AC

Let's calculate the distance from A to C

$A = (x_1,y_1) = (1,2) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-8)^2 + (2-9)^2}\\\\d = \sqrt{(-7)^2 + (-7)^2}\\\\d = \sqrt{49 + 49}\\\\d = \sqrt{98}\\\\d = \sqrt{49*2}\\\\d = \sqrt{49}*\sqrt{2}\\\\d = 7\sqrt{2}\\\\$