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Leto [7]
3 years ago
10

Solve using substitution. y = -10x-10 y = -3x + 4

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0
-10x-10 = -3x+4
+3x +3x
————————
-7x-10 = 4
+10 +10
————————
-7x = 14
then divide -7 on both side of the equal sign
you’ll get x=-2

then plug in -2 as x into one of the equations ( it doesn’t matter which one)

y= -10(-2)-10 = 20-10= 10

so y=10


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Answer:

sixteenxminusfourty-four

Step-by-step explanation:

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How to solve -40=30m-16?
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What I would do for this problem, is move all the terms that don't contain m to the right side, and then solve.
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7 0
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Mary has a pink dress, a blue dress, and a yellow dress. She has a black pair of shoes and a white pair. How many dress and shoe
Yanka [14]
There are two ways to solve this. 
The first way is logically. 
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Count them up, and you'll get six combinations! 

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8 0
3 years ago
Suppose that, after measuring the duration of many telephone calls, a telephone company found their data was well-approximated b
Musya8 [376]

Answer:

a) 7.79%

b) 67.03%

c) Cumulative Distribution Function

P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b

Step-by-step explanation:

We are given the following in the question:

p(x) = 0.1 e^{-0.1x}

where x is the duration of a call, in minutes.

a) P( calls last between 2 and 3 minutes)

=\displaystyle\int^3_2 p(x)~ dx\\\\= \displaystyle\int^3_20.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^3_2\\\\=-\Big[e^{-0.3}-e^{-0.2}\Big]\\\\= 0.0779\\=7.79\%

b) P(calls last 4 minutes or more)

=\displaystyle\int^{\infty}_4 p(x)~ dx\\\\= \displaystyle\int^{\infty}_40.1e^{-0.1x}~dx\\\\=\Big[-e^{-0.1x}\Big]^{\infty}_4\\\\=-\Big[e^{\infty}-e^{-0.4}\Big]\\\\=-(0- 0.6703)\\= 0.6703\\=67.03\%

c) cumulative distribution function

P(t) = \displaystyle\int^{\infty}_{-\infty} 0.1e^{-0.1t}~dt\\\\= \displaystyle\int^{b}_{a} 0.1e^{-0.1t}~dt, ~~a\leq t \leq b

6 0
4 years ago
What is meant by the term outlier? What should you do with an outlier?
saul85 [17]

Outliers are data that are in a very far distance from other values in a set of data

Once an outlier is detected in a set of data, we can do the following to them:

  • Discard the outlier
  • Change the value of the outlier with another value within close range
  • Consider the distribution given

We may have a set of data where some of the <em>values are far in distance from the majority of the data</em>. The set of such data are known as an outlier.

For example, give the set of data;

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45 can be considered as an outlier since the <em>distance of data</em><em> to all other data is</em><em> large</em><em>.</em>

Once an outlier is detected in a set of data, we can do the following to them:

  • Discard the outlier
  • Change the value of the outlier with another value within close range
  • Consider the distribution given

Learn more here: brainly.com/question/23258173

7 0
3 years ago
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