On the Richter scale, the magnitude, M, of an earthquake is given by M= 2/3logE/Eo, where E is the energy released by the earthq
uake measured in joules, and Eo is the energy released by a very small reference earthquake. Eo has been standardized to 10^4.4 joules.
Part A
The earthquake in Haiti in 2010 released 2.0*10^15 joules. What was its magnitude on the Richter scale?
Part B
If the energy release of one earthquake is 10,000 times that of another, how much larger is the Richter scale reading of the larger earthquake than the smaller?
Part A
The earthquake in Haiti in 2010 released 2.0*10^15 joules. What was its magnitude on the Richter scale?
Part B
If the energy release of one earthquake is 10,000 times that of another, how much larger is the Richter scale reading of the larger earthquake than the smaller?
1 answer:
You might be interested in
Answer:
square inches.
Step-by-step explanation:
<h3>Area of the Inscribed Hexagon</h3>Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be inches (same as the length of each side of the regular hexagon.)
Refer to the second attachment for one of these equilateral triangles.
Let segment be a height on side
. Since this triangle is equilateral, the size of each internal angle will be
. The length of segment
.
The area (in square inches) of this equilateral triangle will be:
.
Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:
.
Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is inches, the radius of this circle will also be
inches.
The area (in square inches) of a circle of radius inches is:
.
The area (in square inches) of the circle that the hexagon did not cover would be:
.
