9514 1404 393
Answer:
240 ft by 480 ft
Step-by-step explanation:
Area is maximized when the long side is half the total length of the fence. That makes the short side (out from the river) be half the length of the long side.
The fenced field dimensions are 240 feet by 480 feet.
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You can let x represent the length of the long side. Then the length of the short side is half the remaining fence: (960 -x)/2.
The total area is the product of these dimensions:
A = x(960 -x)/2
We note that this is the equation of a parabola with zeros at x=0 and x=960. The maximum will be found on the line of symmetry, halfway between the zeros. That is at x = (0 +960)/2 = 480.
The area is maximized for a long-side dimension of 480 feet. The short sides are 240 feet.
Step-by-step explanation:
The center of a circle with 2 end points of a di diameter is the midpoint of the two endpoints.
The formula needed to find the minpoints is
(x,y) = (x2 + x1)/2, (y2 + y1)/2
x2 = 3
x1 = 3
y2 = 0
y1 = -7
midpoint = (3 + 3)/2, (0 - 7)/2
midp[oint = 3,-3.5
The midpoint is the center of the circle. Observe that the signs get changed when entering the values for (x,y)
So far what you have is (x - 3)^2 + (y + 3.5)^2 = r^2
To determine r^2 you need only take the distance from the center to oneof the endpoints.
r^2 = (3 - 3)^2 + (3.5 - 0)^2
r^2 = 3.5^2
r^2 = 12.25
Answer: (x - 3)^2 + (y + 3.5)^2 = 12.25
Answer:
158cm
Step-by-step explanation:
154+162=316
316/2=158
Answer:
C) If the perfect square terms are A^2 and B^2 and other terms must be 2 AB and -2AB
Step-by-step explanation:
As,
